Simplify the Product: 1/(ln 4) × 1/(log₈ 10) Logarithmic Expression

Question

1ln41log810= \frac{1}{\ln4}\cdot\frac{1}{\log_810}=

Video Solution

Solution Steps

00:00 Solve
00:04 Convert from radian to log
00:13 Make sure to multiply numerator by numerator and denominator by denominator
00:20 We'll use the formula for log multiplication, switch between bases
00:36 We'll use the formula for 1 divided by log, we'll get the inverse log
00:41 We'll use this formula in our exercise
00:56 We'll solve the log, and substitute in the exercise
01:16 And this is the solution to the question

Step-by-Step Solution

To solve the problem, we must evaluate the expression 1ln41log810\frac{1}{\ln 4} \cdot \frac{1}{\log_8 10}.

First, convert log810\log_8 10 using the change of base formula. We have:

  • log810=ln10ln8\log_8 10 = \frac{\ln 10}{\ln 8}.

Substitute this back into the original expression:

1ln41log810=1ln4ln8ln10\frac{1}{\ln 4} \cdot \frac{1}{\log_8 10} = \frac{1}{\ln 4} \cdot \frac{\ln 8}{\ln 10}.

Next, we need to simplify the expression. We know that ln8=ln(23)=3ln2\ln 8 = \ln (2^3) = 3 \ln 2 and ln4=ln(22)=2ln2\ln 4 = \ln (2^2) = 2 \ln 2.

Substitute these into the expression:

= 12ln23ln2ln10\frac{1}{2 \ln 2} \cdot \frac{3 \ln 2}{\ln 10}.

Simplify by canceling ln2\ln 2:

= 321ln10\frac{3}{2} \cdot \frac{1}{\ln 10}.

Now express ln10=ln(eloge)\ln 10 = \ln (e \cdot \log e), meaning this is equivalent to loge\log e. Continuing, the expression 321loge=32loge\frac{3}{2} \cdot \frac{1}{\log e} = \frac{3}{2} \log e.

Therefore, the simplified solution to the given expression is 32loge\frac{3}{2} \log e.

Answer

32loge \frac{3}{2}\log e