ln41⋅log8101=
To solve the problem, we must evaluate the expression ln41⋅log8101.
First, convert log810 using the change of base formula. We have:
- log810=ln8ln10.
Substitute this back into the original expression:
ln41⋅log8101=ln41⋅ln10ln8.
Next, we need to simplify the expression. We know that ln8=ln(23)=3ln2 and ln4=ln(22)=2ln2.
Substitute these into the expression:
= 2ln21⋅ln103ln2.
Simplify by canceling ln2:
= 23⋅ln101.
Now express ln10=ln(e⋅loge), meaning this is equivalent to loge. Continuing, the expression 23⋅loge1=23loge.
Therefore, the simplified solution to the given expression is 23loge.
23loge