Solve Log₃11/Log₃4 + 2log3/ln3: Logarithmic Expression Challenge

Change of Base with Logarithmic Simplification

log311log34+1ln32log3= \frac{\log_311}{\log_34}+\frac{1}{\ln3}\cdot2\log3=

❤️ Continue Your Math Journey!

We have hundreds of course questions with personalized recommendations + Account 100% premium

Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve
00:03 Let's use the formula for logarithmic division
00:07 We'll get the logarithm of the numerator in base of the denominator
00:13 We'll convert from ln to log
00:20 When dividing 1 by log, we get the inverse log in number and base
00:35 We'll use the formula for logarithmic multiplication, switching between bases
00:50 The logarithm of a number in its own base is always equal to 1
01:01 We'll use the formula for logarithm of a power, putting 2 inside the log
01:10 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

log311log34+1ln32log3= \frac{\log_311}{\log_34}+\frac{1}{\ln3}\cdot2\log3=

2

Step-by-step solution

To solve this problem, we'll proceed as follows:

  • Step 1: Rewrite each logarithmic expression using the change of base formula.
  • Step 2: Simplify the expressions using properties of logarithms.
  • Step 3: Identify the final expression.

Now, let's work through each step:

Step 1: We begin by converting each logarithm to the natural logarithm base.
Using the change of base formula, we have:

log311log34=ln11ln3ln4ln3=ln11ln4 \frac{\log_3 11}{\log_3 4} = \frac{\frac{\ln 11}{\ln 3}}{\frac{\ln 4}{\ln 3}} = \frac{\ln 11}{\ln 4}.

Step 2: Next, simplify the second expression:

1ln32log3=2 \frac{1}{\ln 3} \cdot 2\log 3 = 2.

This follows because log3\log 3 in natural logarithms converts to ln3\ln 3, and thus:

2ln3ln3=2 \frac{2\ln 3}{\ln 3} = 2.

Hence, our entire expression now is ln11ln4+2\frac{\ln 11}{\ln 4} + 2.

Step 3: Express 22 as a logarithm. Using the properties of logarithms:

2=loge22 = \log e^2, since lne=1\ln e = 1.

Therefore, the entire expression becomes:

ln11ln4+loge2 \frac{\ln 11}{\ln 4} + \log e^2.

By the properties of logarithms, this can also be expressed as:

log411+loge2 \log_4 11 + \log e^2.

Thus, the expression simplifies directly to:

log411+loge2 \log_4 11 + \log e^2.

Therefore, the solution to the problem is log411+loge2 \log_4 11 + \log e^2 .

3

Final Answer

log411+loge2 \log_411+\log e^2

Key Points to Remember

Essential concepts to master this topic
  • Change of Base: Convert different bases using logablogac=logcb \frac{\log_a b}{\log_a c} = \log_c b
  • Natural Log Identity: 1ln32log3=2ln3ln3=2 \frac{1}{\ln 3} \cdot 2\log 3 = \frac{2\ln 3}{\ln 3} = 2
  • Check: Verify log411+loge2 \log_4 11 + \log e^2 by converting back to original form ✓

Common Mistakes

Avoid these frequent errors
  • Confusing different logarithm bases
    Don't assume all log symbols mean the same base = wrong conversions! Many students think log 3 always means log₁₀ 3, missing that context matters. Always identify the base clearly: log means base 10, ln means base e, and apply change of base formula correctly.

Practice Quiz

Test your knowledge with interactive questions

\( \frac{1}{\log_49}= \)

FAQ

Everything you need to know about this question

Why does the change of base formula work here?

+

The change of base formula logaxlogay=logyx \frac{\log_a x}{\log_a y} = \log_y x works because both numerator and denominator have the same base. When we divide ln11ln4 \frac{\ln 11}{\ln 4} , we get log411 \log_4 11 !

What's the difference between log and ln in this problem?

+

ln means natural logarithm (base e), while log typically means base 10. In 1ln32log3 \frac{1}{\ln 3} \cdot 2\log 3 , we have both types, but they cancel out to give us 2.

How do I know when to use the change of base formula?

+

Use it when you see division of logarithms with the same base! Like log311log34 \frac{\log_3 11}{\log_3 4} - both have base 3, so you can convert to log411 \log_4 11 .

Why does 2 become log e²?

+

Any number can be written as a logarithm! Since lne=1 \ln e = 1 , we have lne2=2lne=2 \ln e^2 = 2 \ln e = 2 . Using base 10: 2=loge2 2 = \log e^2 .

Can I solve this without the change of base formula?

+

You could use calculators to get decimal approximations, but the exact algebraic form log411+loge2 \log_4 11 + \log e^2 is much more elegant and shows the mathematical relationships clearly!

🌟 Unlock Your Math Potential

Get unlimited access to all 24 Rules of Logarithms questions, detailed video solutions, and personalized progress tracking.

📹

Unlimited Video Solutions

Step-by-step explanations for every problem

📊

Progress Analytics

Track your mastery across all topics

🚫

Ad-Free Learning

Focus on math without distractions

No credit card required • Cancel anytime

More Questions

Click on any question to see the complete solution with step-by-step explanations