log34log311+ln31⋅2log3=
To solve this problem, we'll proceed as follows:
- Step 1: Rewrite each logarithmic expression using the change of base formula.
- Step 2: Simplify the expressions using properties of logarithms.
- Step 3: Identify the final expression.
Now, let's work through each step:
Step 1: We begin by converting each logarithm to the natural logarithm base.
Using the change of base formula, we have:
log34log311=ln3ln4ln3ln11=ln4ln11.
Step 2: Next, simplify the second expression:
ln31⋅2log3=2.
This follows because log3 in natural logarithms converts to ln3, and thus:
ln32ln3=2.
Hence, our entire expression now is ln4ln11+2.
Step 3: Express 2 as a logarithm. Using the properties of logarithms:
2=loge2, since lne=1.
Therefore, the entire expression becomes:
ln4ln11+loge2.
By the properties of logarithms, this can also be expressed as:
log411+loge2.
Thus, the expression simplifies directly to:
log411+loge2.
Therefore, the solution to the problem is log411+loge2.
log411+loge2