Solve: log₈(x³)/log₈(x^1.5) + log₇(x⁵)/log₄₉(x) Logarithmic Expression

Question

log8x3log8x1.5+1log49x×log7x5= \frac{\log_8x^3}{\log_8x^{1.5}}+\frac{1}{\log_{49}x}\times\log_7x^5=

Video Solution

Solution Steps

00:00 Solve
00:06 We'll use the formula for logarithmic division
00:11 We'll get the log of the numerator in base of the denominator
00:16 We'll use this formula in our exercise
00:26 We'll raise the product to the numerator
00:41 We'll solve the logarithm
01:07 We'll put this solution in the exercise and continue solving
01:22 We'll use the formula for 1 divided by log
01:27 We'll get the inverse logarithm in base and number
01:32 We'll use this formula in our exercise
01:42 We'll use the formula for logarithmic multiplication, we'll switch between the numbers
01:57 We'll use this formula in our exercise
02:12 We'll calculate each logarithm separately and put it in the exercise
02:57 And this is the solution to the question

Step-by-Step Solution

To solve the given problem, we begin by simplifying each component of the expression.

Step 1: Simplify log8x3log8x1.5 \frac{\log_8x^3}{\log_8x^{1.5}} .
Applying the power rule of logarithms, we get:
log8x3=3log8x \log_8x^3 = 3 \log_8x , and log8x1.5=1.5log8x \log_8x^{1.5} = 1.5 \log_8x .
Thus, 3log8x1.5log8x=31.5=2 \frac{3 \log_8x}{1.5 \log_8x} = \frac{3}{1.5} = 2 .

Step 2: Simplify 1log49x×log7x5 \frac{1}{\log_{49}x} \times \log_7x^5 .
First, notice that log7x5=5log7x \log_7x^5 = 5 \log_7x by the power rule.
Applying the change of base formula, log49x=log7xlog749=log7x2 \log_{49}x = \frac{\log_7x}{\log_749} = \frac{\log_7x}{2} because 49=72 49 = 7^2 .
This gives 1log49x=2log7x \frac{1}{\log_{49}x} = \frac{2}{\log_7x} .
Therefore, 2log7x×5log7x=2×5=10 \frac{2}{\log_7x} \times 5 \log_7x = 2 \times 5 = 10 .

Step 3: Combine the results from Step 1 and Step 2.
The simplified expression is 2+10=12 2 + 10 = 12 .

Therefore, the solution to the problem is 12 12 .

Answer

12 12


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