Solve: 2^3 × 2^4 + (4^3)^2 + 2^5/2^3 - Complete Exponent Expression

Solve the following exercise:

23×24+(43)2+2523= 2^3\times2^4+(4^3)^2+\frac{2^5}{2^3}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve the following problem
00:03 When multiplying powers with equal bases
00:08 The power of the result equals the sum of the powers
00:13 We'll apply this formula to our exercise
00:18 When there's a power of a power, the combined power is the product of the powers
00:24 We'll apply this formula to our exercise
00:28 When dividing powers with equal bases
00:31 The power of the result equals the difference of the powers
00:38 We'll apply this formula to our exercise
00:50 Let's calculate all the powers
00:58 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following exercise:

23×24+(43)2+2523= 2^3\times2^4+(4^3)^2+\frac{2^5}{2^3}=

2

Step-by-step solution

We use the three appropriate power properties to solve the problem:

  1. Power law for multiplication between terms with identical bases:

aman=am+n a^m\cdot a^n=a^{m+n} 2. Power law for an exponent raised to another exponent:

(am)n=amn (a^m)^n=a^{m\cdot n} 3. Power law for the division of terms with identical bases:

aman=amn \frac{a^m}{a^n}=a^{m-n}

We continue and apply the three previous laws to the problem:

2324+(43)2+2523=23+4+432+253=27+46+22 2^3\cdot2^4+(4^3)^2+\frac{2^5}{2^3}=2^{3+4}+4^{3\cdot2}+2^{5-3}=2^7+4^6+2^2

In the first step we apply the power law mentioned in point 1 to the first expression on the left, the power law mentioned in point 2 to the second expression on the left, and the power law mentioned in point 3 to the third expression on the left, separately. In the second step, we simplify the expressions by exponents possession of the received terms,

Then,after using the substitution property for addition, we find that the correct answer is D.

3

Final Answer

22+27+46 2^2+2^7+4^6

Practice Quiz

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\( 112^0=\text{?} \)

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