Solve [(4-2)²]³: A Triple Exponent Challenge

Order of Operations with Nested Exponents

[(42)2]3= [(4-2)^2]^3=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:06 Let's solve this math expression, step by step.
00:09 First, we always calculate what's inside the parentheses.
00:14 Next, we calculate the square of the number.
00:17 Now, let's break down the power and solve it.
00:21 Let's solve the first multiplication.
00:24 Break the number sixteen into ten plus six.
00:28 Open the parentheses, and multiply by each part.
00:33 Now, solve each multiplication, then add them together.
00:37 Great work! That's how you find the solution.

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

[(42)2]3= [(4-2)^2]^3=

2

Step-by-step solution

To solve the expression [(42)2]3 [(4-2)^2]^3 , we need to follow the order of operations, often remembered by the acronym PEMDAS (Parentheses, Exponents, Multiplication and Division, Addition and Subtraction).

Step 1: Solve the innermost parentheses:

The expression inside the innermost parentheses is 424-2. We perform the subtraction:

42=24-2 = 2

Step 2: Apply the exponentiation:

Next, we take the result of the subtraction and apply the squaring operation ((2)2)((2)^2):

22=42^2 = 4

Step 3: Apply the outer exponentiation:

Finally, we take the result of the previous step and raise it to the power of 3:

43=644^3 = 64

Therefore, the value of the expression [(42)2]3 [(4-2)^2]^3 is 6464.

3

Final Answer

64

Key Points to Remember

Essential concepts to master this topic
  • PEMDAS Rule: Work inside parentheses first, then exponents from inside out
  • Technique: Calculate (4-2) = 2, then 2² = 4, finally 4³ = 64
  • Check: Verify each step: 2 × 2 = 4, then 4 × 4 × 4 = 64 ✓

Common Mistakes

Avoid these frequent errors
  • Applying exponents in wrong order
    Don't calculate [(4-2)²]³ as (4-2)^(2×3) = 2⁶ = 64! This treats it like a power rule instead of nested operations. Always work from innermost parentheses outward: first (4-2)² = 4, then [4]³ = 64.

Practice Quiz

Test your knowledge with interactive questions

\( 20\div(4+1)-3= \)

FAQ

Everything you need to know about this question

Why can't I just multiply the exponents 2 × 3?

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The power rule (am)n=amn (a^m)^n = a^{mn} only applies when you have the same base. Here we have [(42)2]3 [(4-2)^2]^3 , where the base changes from (4-2) to 4 after the first exponent.

What if I forgot to do the subtraction first?

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Always follow PEMDAS! Parentheses come first, so you must calculate 4-2 = 2 before applying any exponents. Skipping this step will give you completely wrong answers.

How do I keep track of all these steps?

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Write each step clearly:

  • Step 1: (4-2) = 2
  • Step 2: [2²] = [4]
  • Step 3: [4]³ = 64

This prevents confusion and helps you catch mistakes!

Is there a shortcut for nested exponents?

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No safe shortcuts exist! Each set of brackets must be calculated separately. Trying to skip steps often leads to errors. Work systematically from innermost to outermost operations.

What's the difference between [2²]³ and 2^(2×3)?

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[22]3=[4]3=64 [2^2]^3 = [4]^3 = 64 (nested operations), while 22×3=26=64 2^{2×3} = 2^6 = 64 (power rule). They happen to equal the same here, but this is not always true!

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