Solve (4²)³ + (g³)⁴: Multiple Exponent Expression Problem

Question

(42)3+(g3)4= (4^2)^3+(g^3)^4=

Video Solution

Step-by-Step Solution

We use the formula:

(am)n=am×n (a^m)^n=a^{m\times n}

(42)3+(g3)4=42×3+g3×4=46+g12 (4^2)^3+(g^3)^4=4^{2\times3}+g^{3\times4}=4^6+g^{12}

Answer

46+g12 4^6+g^{12}

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Related Subjects

Exponents and Exponent rules Rules of Exponentiation Combining Powers and Roots Properties of Exponents Power of a Power

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Applying Combined Exponents Rules: Applying the formula Applying Combined Exponents Rules: A power law Applying Combined Exponents Rules: Monomial Applying Combined Exponents Rules: Single Variable Power of a Power: Applying the formula