Solve (4x+22)² > 0: Finding Values of x in a Perfect Square Inequality

Perfect Square Inequalities with Zero Values

Look at the function below:

y=(4x+22)2 y=\left(4x+22\right)^2

Then determine for which values of x x the following is true:

f(x)>0 f(x) > 0

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Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Look at the function below:

y=(4x+22)2 y=\left(4x+22\right)^2

Then determine for which values of x x the following is true:

f(x)>0 f(x) > 0

2

Step-by-step solution

To solve this problem, we observe that the function given is y=(4x+22)2 y = (4x + 22)^2 .

Step 1: We set the expression inside the square equal to zero and solve for x x .
4x+22=0 4x + 22 = 0

Step 2: Solve the equation above for x x :

4x+22=04x=22x=224=5.5 4x + 22 = 0 \\ 4x = -22 \\ x = -\frac{22}{4} = -5.5

This calculation reveals that x=5.5 x = -5.5 is the only point where (4x+22)2=0 (4x + 22)^2 = 0 .

Step 3: Outside of this specific x x , the squared term (4x+22)2 (4x+22)^2 is positive for all other values of x x .

Therefore, the function is positive (f(x)>0) (f(x) > 0) when x5.5 x \neq -5.5 .

Thus, the solution to the problem is: x512 x \neq -5\frac{1}{2} .

3

Final Answer

x512 x\ne-5\frac{1}{2}

Key Points to Remember

Essential concepts to master this topic
  • Square Property: Any squared expression is always non-negative
  • Technique: Set 4x+22=0 4x + 22 = 0 to find where expression equals zero
  • Check: At x=5.5 x = -5.5 , (4(5.5)+22)2=0 (4(-5.5) + 22)^2 = 0

Common Mistakes

Avoid these frequent errors
  • Thinking squared expressions can be negative
    Don't assume (4x+22)2 (4x+22)^2 can be less than zero = impossible result! Squared expressions are always ≥ 0, never negative. Always remember that any real number squared gives a positive result or zero.

Practice Quiz

Test your knowledge with interactive questions

The graph of the function below intersects the X-axis at points A and B.

The vertex of the parabola is marked at point C.

Find all values of \( x \) where \( f\left(x\right) > 0 \).

AAABBBCCCX

FAQ

Everything you need to know about this question

Why can't a squared expression be negative?

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When you square any real number, you always get a positive result or zero. For example: 32=9 3^2 = 9 and (3)2=9 (-3)^2 = 9 . This is a fundamental property of squares!

What does the notation x ≠ -5½ mean exactly?

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This means all real numbers except -5.5. So x can be any value like -6, -2, 0, 10, etc., but it cannot equal -5.5 because that's where the function equals zero, not greater than zero.

How do I solve 4x + 22 = 0 step by step?

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Start with 4x+22=0 4x + 22 = 0
Subtract 22: 4x=22 4x = -22
Divide by 4: x=224=5.5 x = -\frac{22}{4} = -5.5

Why isn't the answer 'all x' since squares are always positive?

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Great thinking! Squares are always non-negative (≥ 0), but we need strictly greater than zero (> 0). At x=5.5 x = -5.5 , the function equals exactly 0, which doesn't satisfy f(x) > 0.

How can I verify this answer makes sense?

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Test a few values! Try x=0 x = 0 : (4(0)+22)2=222=484>0 (4(0)+22)^2 = 22^2 = 484 > 0
Try x=6 x = -6 : (4(6)+22)2=(2)2=4>0 (4(-6)+22)^2 = (-2)^2 = 4 > 0
Only at x=5.5 x = -5.5 does it equal 0.

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