Solve (4x+22)² < 0: Finding Values for Negative Quadratic Output

Squared Expressions with Non-negative Properties

Look at the function below:

y=(4x+22)2 y=\left(4x+22\right)^2

Then determine for which values of x x the following is true:

f(x)<0 f(x) < 0

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Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Look at the function below:

y=(4x+22)2 y=\left(4x+22\right)^2

Then determine for which values of x x the following is true:

f(x)<0 f(x) < 0

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Analyze the given function.
  • Step 2: Determine the nature of (4x+22)2 (4x + 22)^2 .
  • Step 3: Conclude whether it can ever be negative.

Step 1: We are given the function y=(4x+22)2 y = (4x + 22)^2 . This is a quadratic function expressed as a square of a linear term.

Step 2: Consider the expression (4x+22) (4x + 22) . Whatever value this linear expression takes, its square, (4x+22)2 (4x + 22)^2 , will always be non-negative. This is because the square of a real number is never negative.

Step 3: To find when (4x+22)2<0 (4x + 22)^2 < 0 , we realize that since squares are non-negative, they cannot actually be negative. Thus, (4x+22)20 (4x + 22)^2 \geq 0 for all values of x x , and can never be less than zero.

Therefore, no value of x x will make f(x)<0 f(x) < 0 .

The conclusion is that there is no value of x x for which f(x)<0 f(x) < 0 .

3

Final Answer

No value of x x

Key Points to Remember

Essential concepts to master this topic
  • Rule: Any squared expression equals zero or positive value
  • Technique: (4x+22)20 (4x + 22)^2 \geq 0 for all real x values
  • Check: Test any x value: when x = 0, (22)2=484>0 (22)^2 = 484 > 0

Common Mistakes

Avoid these frequent errors
  • Assuming squared expressions can be negative
    Don't think (4x+22)2 (4x + 22)^2 can be negative = impossible solutions! Squares of real numbers are always non-negative. Always remember that a20 a^2 \geq 0 for any real number a.

Practice Quiz

Test your knowledge with interactive questions

The graph of the function below does not intersect the \( x \)-axis.

The parabola's vertex is marked A.

Find all values of \( x \) where
\( f\left(x\right) > 0 \).

AAAX

FAQ

Everything you need to know about this question

Why can't a squared number be negative?

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When you multiply any real number by itself, the result is always zero or positive. For example: 32=9 3^2 = 9 and (3)2=9 (-3)^2 = 9 . Even negative numbers become positive when squared!

What does it mean when there are no solutions?

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It means the inequality cannot be satisfied by any real number. Since (4x+22)2 (4x + 22)^2 is never negative, there's no value of x that makes it less than zero.

Could the expression equal zero instead?

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Yes! (4x+22)2=0 (4x + 22)^2 = 0 when 4x+22=0 4x + 22 = 0 , so x=512 x = -5\frac{1}{2} . But the question asks for when it's less than zero, which never happens.

How do I recognize when an inequality has no solutions?

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Look for squared expressions being compared to negative numbers. Since squares are never negative, inequalities like x2<0 x^2 < 0 or (anything)2<0 (anything)^2 < 0 have no solutions.

What if the inequality was greater than zero instead?

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Then almost all real numbers would work! (4x+22)2>0 (4x + 22)^2 > 0 is true for all x except x=512 x = -5\frac{1}{2} where the expression equals zero.

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