Solve (3x+30)² > 0: Finding Positive Values of a Quadratic Function

Squared Functions with Zero Analysis

Look at the function below:

y=(3x+30)2 y=\left(3x+30\right)^2

Then determine for which values of x x the following is true:

f(x)>0 f(x) > 0

❤️ Continue Your Math Journey!

We have hundreds of course questions with personalized recommendations + Account 100% premium

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Look at the function below:

y=(3x+30)2 y=\left(3x+30\right)^2

Then determine for which values of x x the following is true:

f(x)>0 f(x) > 0

2

Step-by-step solution

To determine the values of x x for which the function y=(3x+30)2 y = (3x + 30)^2 is greater than zero, consider the following steps:

  • Step 1: Recognize the structure of the function. The function is of the form (expression)2 (\text{expression})^2 . For the function to be greater than zero, the expression inside the square must not equal zero.
  • Step 2: Solve 3x+30=0 3x + 30 = 0 to find when the function equals zero.
    Subtract 30 from both sides: 3x=30 3x = -30 .
    Divide by 3: x=10 x = -10 .
  • Step 3: Exclude x=10 x = -10 from the domain where the function is greater than 0. For all x10 x \neq -10 , (3x+30)2 (3x + 30)^2 is positive because it results from squaring a non-zero real number.

Therefore, f(x)>0 f(x) > 0 for all x10 x \neq -10 .

The correct answer is x10 x\ne-10 .

3

Final Answer

x10 x\ne-10

Key Points to Remember

Essential concepts to master this topic
  • Rule: Squared expressions are positive except when the base equals zero
  • Technique: Set 3x + 30 = 0, solve to find x = -10
  • Check: Test x ≠ -10: (3(-9) + 30)² = 3² = 9 > 0 ✓

Common Mistakes

Avoid these frequent errors
  • Thinking squared functions are always positive
    Don't assume (3x + 30)² > 0 for ALL x values = includes zero incorrectly! When 3x + 30 = 0, the squared result is 0, not positive. Always find where the expression inside equals zero and exclude that value.

Practice Quiz

Test your knowledge with interactive questions

The graph of the function below does not intersect the \( x \)-axis.

The parabola's vertex is marked A.

Find all values of \( x \) where
\( f\left(x\right) > 0 \).

AAAX

FAQ

Everything you need to know about this question

Why isn't the answer 'true for all values of x'?

+

Because when x = -10, we get (3(10)+30)2=02=0 (3(-10) + 30)^2 = 0^2 = 0 , and 0 is not greater than 0. We need strictly positive values!

How do I remember when squared expressions equal zero?

+

A squared expression equals zero only when the base equals zero. So solve 3x+30=0 3x + 30 = 0 to find the excluded value: x = -10.

What's the difference between > 0 and ≥ 0?

+

The symbol > 0 means 'strictly greater than zero' (excludes 0), while ≥ 0 means 'greater than or equal to zero' (includes 0). This problem asks for > 0!

Can I just say x > -10 instead of x ≠ -10?

+

No! The function is positive for both x > -10 and x < -10. Only x = -10 makes it zero. So we need x10 x \neq -10 to include all positive values.

How can I verify my answer is correct?

+

Test values on both sides of x = -10: try x = -11 and x = -9. Both should give positive results: (3(11)+30)2=(3)2=9>0 (3(-11) + 30)^2 = (-3)^2 = 9 > 0

🌟 Unlock Your Math Potential

Get unlimited access to all 18 The Quadratic Function questions, detailed video solutions, and personalized progress tracking.

📹

Unlimited Video Solutions

Step-by-step explanations for every problem

📊

Progress Analytics

Track your mastery across all topics

🚫

Ad-Free Learning

Focus on math without distractions

No credit card required • Cancel anytime

More Questions

Click on any question to see the complete solution with step-by-step explanations