Solve: (a+b+c)÷((3a+3b+3c)/2) - Expression Division Problem

Question

Solve the following problem:

$(a+b+c):(\frac{3a+3b+3c}{2})=\text{?}$

00:10 Alright, let's solve this problem together.

00:13 Remember, division is like multiplying by the reciprocal. So, flip the second fraction and multiply.

00:30 Multiply the top numbers, or numerators, and the bottom numbers, or denominators. Step by step.

00:38 Now, look for a common factor. Let's take out the common factor, which is three, from the parentheses.

00:45 Great! Reduce what you can. We are almost there.

00:51 And there you have it! That's the solution to the question.

Let's flip the fraction to get a multiplication exercise:

$(a+b+c)\times(\frac{2}{3a+3b+3c})=$

We'll add the expression in the first parentheses to the numerator of the fraction:

$\frac{2(a+b+c)}{3a+3b+3c}=$

We'll write the denominator of the fraction as a multiplication exercise:

$\frac{2(a+b+c)}{3(a+b+c)}=$

Let's simplify a+b+c:

$\frac{2}{3}$

$\frac{2}{3}$