Solve for the Missing Addend: 3⅔ + ? = 6

To solve $3\frac{2}{3} + ? = 6$, we need to determine what number, when added to the mixed fraction $3\frac{2}{3}$, results in 6.

Follow these steps:

• Convert the mixed number to an improper fraction:
  $3\frac{2}{3} = 3 + \frac{2}{3} = \frac{3 \times 3 + 2}{3} = \frac{9 + 2}{3} = \frac{11}{3}$.
• Determine the number needed to reach 6:
  We rewrite the equation as $6 - \frac{11}{3}$.
• Convert 6 to a fraction with a denominator of 3:
  $6 = \frac{6 \times 3}{3} = \frac{18}{3}$.
• Subtract the improper fraction from 6:
  $\frac{18}{3} - \frac{11}{3} = \frac{18 - 11}{3} = \frac{7}{3}$.
• Convert the result back to a mixed number:
  $\frac{7}{3} = 2 \frac{1}{3}$ since $7 \div 3 = 2$ remainder $1$.

Therefore, the missing number is $2\frac{1}{3}$.

The correct answer from the given choices is Option 3: $2\frac{1}{3}$.