Solve for x: Finding the Multiplicative Inverse in x·y Expression

Division Cancellation with Algebraic Fractions

x:(xy)=? x:(x\cdot y)=\text{?}

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Step-by-step video solution

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00:00 Solve
00:03 Let's write division as a fraction
00:07 Let's reduce what we can
00:11 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

x:(xy)=? x:(x\cdot y)=\text{?}

2

Step-by-step solution

Let's write the expression as a fraction:

xx×y= \frac{x}{x\times y}=

We'll reduce between the x in the numerator and denominator and get:

1y \frac{1}{y}

3

Final Answer

1y \frac{1}{y}

Key Points to Remember

Essential concepts to master this topic
  • Division Rule: Division can be written as a fraction for simplification
  • Technique: Cancel common factors: xxy=1y \frac{x}{x \cdot y} = \frac{1}{y}
  • Check: Multiply result by divisor: 1y(xy)=x \frac{1}{y} \cdot (x \cdot y) = x

Common Mistakes

Avoid these frequent errors
  • Canceling variables incorrectly in division
    Don't cancel just any x you see = wrong simplification! Students often cancel x from both numerator and denominator without understanding what they're dividing. Always rewrite division as a fraction first, then identify what cancels.

Practice Quiz

Test your knowledge with interactive questions

\( 100-(5+55)= \)

FAQ

Everything you need to know about this question

Why do we write division as a fraction?

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Writing x÷(xy) x \div (x \cdot y) as xxy \frac{x}{x \cdot y} makes it easier to see what cancels. The fraction form clearly shows the numerator and denominator.

Can I always cancel the same variables?

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Yes, but be careful! You can only cancel variables that appear as factors (being multiplied), not as terms (being added or subtracted). In xxy \frac{x}{x \cdot y} , x is a factor in both parts.

What if x equals zero?

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Great question! If x=0 x = 0 , then the original expression x÷(xy) x \div (x \cdot y) becomes 0÷0 0 \div 0 , which is undefined. We assume x0 x ≠ 0 for this problem.

Why isn't the answer just 1?

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Many students think xxy=1 \frac{x}{x \cdot y} = 1 , but that's incomplete cancellation! When you cancel the x's, you get 1y \frac{1}{y} , not 1. The y stays in the denominator.

How can I check if my answer is right?

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Multiply your answer by the original divisor: 1y×(xy)=xyy=x \frac{1}{y} \times (x \cdot y) = \frac{x \cdot y}{y} = x . Since you get back to x, your answer is correct!

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