Solve Log₂x + Log₂(x/2) = 5: Finding the Value of x

log2x+log2x2=5 \log_2x+\log_2\frac{x}{2}=5

?=x

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Step-by-step video solution

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00:00 Solve
00:04 Find the domain of definition for X
00:17 We'll use the formula for adding logarithms, we'll get the logarithm of their product
00:27 We'll use this formula in our exercise
00:35 Calculate the product
00:48 Solve according to the logarithm definition
00:53 Isolate X
01:02 When extracting a root, there will always be 2 solutions: positive and negative
01:05 Find the solution according to the domain of definition
01:08 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

log2x+log2x2=5 \log_2x+\log_2\frac{x}{2}=5

?=x

2

Step-by-step solution

To solve this equation, we follow these steps:

  • Step 1: Use the property of logarithms logba+logbc=logb(ac) \log_b a + \log_b c = \log_b (a \cdot c) to combine terms on the left-hand side of the equation.
  • Step 2: Simplify the expression under the logarithm and solve for x x .

Let's proceed through these steps:

Step 1: Rewrite the equation using logarithmic properties:
log2x+log2x2=log2x+log2xlog22\log_2 x + \log_2 \frac{x}{2} = \log_2 x + \log_2 x - \log_2 2

This simplifies to:
2log2x1=52 \log_2 x - 1 = 5

Step 2: Solve the equation:
Add 1 to both sides:

2log2x=6 2 \log_2 x = 6

Divide both sides by 2:

log2x=3 \log_2 x = 3

Now, convert the logarithmic equation to its exponential form:

x=23 x = 2^3

Calculate x x :

x=8 x = 8

Therefore, the solution to the problem is x=8 x = 8 .

3

Final Answer

8 8

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\( \frac{1}{\log_49}= \)

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