Solve Mixed Number Expression: 3(b/a)×1⅜a + ⅝b + Other Terms

Question

3ba138a+58b+418m+910a+23m=? 3\frac{b}{a}\cdot1\frac{3}{8}a+\frac{5}{8}b+\frac{4}{18}m+\frac{9}{10}a+\frac{2}{3}m=\text{?}

Video Solution

Step-by-Step Solution

To solve this problem, we'll simplify the algebraic expression and combine like terms:

  • Convert mixed numbers to improper fractions and simplify.
  • Simplify each part of the expression.
  • Combine like terms by variable type.

Let's go through each step:

First, convert and simplify 3ba138a3\frac{b}{a} \cdot 1\frac{3}{8}a: - Change 1381\frac{3}{8} to an improper fraction: 138=1181\frac{3}{8} = \frac{11}{8}.

Thus, multiply: 3ba118a=33b83\frac{b}{a} \cdot \frac{11}{8}a = \frac{33b}{8}.

Then, look at each term:

  • The expression now consists of: 33b8+58b+910a+418m+23m \frac{33b}{8} + \frac{5}{8}b + \frac{9}{10}a + \frac{4}{18}m + \frac{2}{3}m .
  • Simplify each component: - 418m=29m\frac{4}{18}m = \frac{2}{9}m (reducing the fraction).
  • Now, add like terms: - Combine terms involving bb: 33b8+5b8=33b+5b8=38b8=434b\frac{33b}{8} + \frac{5b}{8} = \frac{33b + 5b}{8} = \frac{38b}{8} = 4\frac{3}{4}b.
  • There are no like terms with aa, so 910a\frac{9}{10}a remains unchanged.
  • Combine terms involving mm: 29m+23m=2m9+6m9=8m9\frac{2}{9}m + \frac{2}{3}m = \frac{2m}{9} + \frac{6m}{9} = \frac{8m}{9}.

After the simplification, the expression becomes: 434b+910a+89m4\frac{3}{4}b + \frac{9}{10}a + \frac{8}{9}m.

Therefore, the solution to the problem is 434b+910a+89m4\frac{3}{4}b + \frac{9}{10}a + \frac{8}{9}m.

Answer

434b+910a+89m 4\frac{3}{4}b+\frac{9}{10}a+\frac{8}{9}m