Solve: (3z/4 + 1/4m + 12/13z⋅4/5m + 1/7z) Combined Expression

Question

3z4+14m+1213z45m+17z=? \frac{3z}{4}+\frac{1}{4}m+\frac{12}{13}z\cdot\frac{4}{5}m+\frac{1}{7}z=\text{?}

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Identify and combine like terms involving z z .

  • Simplify the term involving both z z and m m .

  • Combine and simplify fractions.

Now, let us solve the expression step-by-step:

Given expression: 3z4+14m+1213z45m+17z \frac{3z}{4} + \frac{1}{4}m + \frac{12}{13}z \cdot \frac{4}{5}m + \frac{1}{7}z

Step 1: Combine like terms for z z .

Terms involving z z are: 3z4 \frac{3z}{4} , 17z \frac{1}{7}z .

To combine these, we need a common denominator. The least common multiple of 4 and 7 is 28:

3z4=21z28 \frac{3z}{4} = \frac{21z}{28} and 1z7=4z28 \frac{1z}{7} = \frac{4z}{28} .

Add these: 21z28+4z28=25z28 \frac{21z}{28} + \frac{4z}{28} = \frac{25z}{28} .

Step 2: Simplify the term involving both z z and m m .

1213z45m=4865zm \frac{12}{13}z \cdot \frac{4}{5}m = \frac{48}{65}zm .

This expression is already in its simplest form.

Step 3: Write the whole expression in simplified form:

25z28+14m+4865zm \frac{25z}{28} + \frac{1}{4}m + \frac{48}{65}zm .

Therefore, the simplified expression is: 2528z+14m+4865zm \frac{25}{28}z + \frac{1}{4}m + \frac{48}{65}zm .

Answer

2528z+14m+4865zm \frac{25}{28}z+\frac{1}{4}m+\frac{48}{65}zm