Solve: Multiplying Algebraic Fractions (9m/3m² × 3m/6)

There's an error in the given explanation! It incorrectly canceled all the m variables. The correct solution keeps one m: $\frac{9m \times 3m}{3m^2 \times 6} = \frac{27m^2}{18m^2} = \frac{27}{18m} = \frac{3}{2m}$, but this doesn't match either answer.

Look for identical factors in both numerator and denominator. In this problem, you can cancel $m^2$ terms, but be careful not to cancel variables that appear with different powers!

Yes! Cancel numerical factors first: $\frac{9 \times 3}{3 \times 6} = \frac{27}{18} = \frac{3}{2}$, then handle variables: $\frac{m \times m}{m^2} = \frac{m^2}{m^2} = 1$

These are completely different! 0.5m means "half of m" (contains a variable), while 1.5 is just a number. The correct answer should contain m since the original problem has variables.

Pick any value for the variable (like m=2) and substitute it into both the original expression and your answer. If they give the same result, you're correct!