Solve the Logarithmic Equation: log₄(x²)·log₇16 = 2log₇8
Question
log4x2⋅log716=2log78
?=x
Video Solution
Solution Steps
00:00Solve
00:03Find the domain of definition
00:16We'll use the formula for logarithmic multiplication, we'll switch between the bases
00:31We'll use this formula in our exercise
00:41Let's calculate the logarithm
00:56We'll substitute in our exercise and continue solving
01:06Let's simplify what we can
01:16We'll compare the numbers, since the bases are equal
01:21When extracting a root there are always 2 solutions, positive and negative
01:25And this is the solution to the problem
Step-by-Step Solution
To solve this logarithmic equation, we will break down and simplify the given expression step by step:
Step 1: Simplify each logarithm using the change of base formula.
First, consider log4x2:
Using the power rule, log4x2=2log4x.
Now apply the change of base formula: log4x=log4logx, thus log4x2=2⋅log4logx.
Step 2: Simplify log716 and log78 using the change of base formula. log716=log7log16=log7log(24)=log74log2.
Similarly, log78=log7log8=log7log(23)=log73log2.
Step 3: Substitute these values back into the equation. log42logx⋅log74log2=2⋅log73log2
Step 4: Simplify the equation by canceling out common terms and solving for logx.
After cancelling log7log2 from both sides, we have: log48logx=6.
Step 5: Calculate log4=2log2, so substitute: 2log28logx=6⟹4logx=6log2, thus logx=23log2.
Step 6: Solve for x using exponentiation.
Since logx=23log2, exponentiation gives x=223=8. However, since logarithms are defined for positive numbers, we must consider ± for solutions within the constraints. Thus, x=±8.
Therefore, the solution to the problem is x=±8, corresponding to choice 4.