Solve (y×x×3)^5: Multiple Variable Exponent Evaluation

Exponent Rules with Multiple Variables

(y×x×3)5= (y\times x\times3)^5=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:08 Let's simplify the expression together!
00:11 Remember, if a product has a power, each term is raised to that power.
00:22 We'll apply this rule in the exercise now.
00:25 Raise each part to the given power.
00:29 And there you have it! That's how we solve it.

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

(y×x×3)5= (y\times x\times3)^5=

2

Step-by-step solution

We use the formula:

(a×b)n=anbn (a\times b)^n=a^nb^n

(y×x×3)5=y5x535 (y\times x\times3)^5=y^5x^53^5

3

Final Answer

y5×x5×35 y^5\times x^5\times3^5

Key Points to Remember

Essential concepts to master this topic
  • Power Rule: When raising a product to a power, raise each factor to that power
  • Technique: (abc)n=an×bn×cn (abc)^n = a^n \times b^n \times c^n distributes the exponent to all factors
  • Check: Verify each variable and constant has the same exponent as the original power ✓

Common Mistakes

Avoid these frequent errors
  • Only applying the exponent to one factor
    Don't raise just one variable to the 5th power like y5×x×3 y^5 \times x \times 3 = wrong result! This ignores the distributive property of exponents. Always raise every single factor inside the parentheses to the given power.

Practice Quiz

Test your knowledge with interactive questions

\( 112^0=\text{?} \)

FAQ

Everything you need to know about this question

Why does the exponent apply to every factor inside the parentheses?

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The power of a product rule states that (ab)n=an×bn (ab)^n = a^n \times b^n . This means the exponent distributes to every factor, whether it's a variable like y or x, or a constant like 3.

What if I have different variables mixed together?

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It doesn't matter! The rule works the same way. Each variable gets raised to the power separately: (abc)5=a5b5c5 (abc)^5 = a^5b^5c^5 . Variables don't interfere with each other.

Does this work with negative exponents too?

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Yes! The power rule works with any exponent. For example: (xy)2=x2y2 (xy)^{-2} = x^{-2}y^{-2} . The exponent always distributes to every factor.

How can I remember this rule?

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Think of it as sharing equally! When you have (abc)5 (abc)^5 , imagine the exponent 5 making 5 copies of the entire product, which gives each factor the same power.

What's the difference between this and adding exponents?

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You add exponents when multiplying the same base: x2×x3=x5 x^2 \times x^3 = x^5 . You distribute exponents when raising a product to a power: (xy)3=x3y3 (xy)^3 = x^3y^3 .

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