Addition of Fractions: The common denominator is smaller than the product of the denominators

To solve this problem, we'll follow these steps:

• Step 1: Determine the least common denominator of 4 and 6.
• Step 2: Convert each fraction to this common denominator.
• Step 3: Add the numerators and form the resultant fraction.
• Step 4: Simplify the resulting fraction if necessary.

Now, let's work through each step:
Step 1: The denominators are 4 and 6. The least common multiple of 4 and 6 is 12.

Step 2: Convert each fraction to have the denominator 12.
For $\frac{1}{4}$, multiplying the numerator and denominator by 3 gives $\frac{1 \times 3}{4 \times 3} = \frac{3}{12}$.
For $\frac{2}{6}$, multiplying the numerator and denominator by 2 gives $\frac{2 \times 2}{6 \times 2} = \frac{4}{12}$.

Step 3: Add the fractions: $\frac{3}{12} + \frac{4}{12} = \frac{3 + 4}{12} = \frac{7}{12}$.

Step 4: Check if $\frac{7}{12}$ can be simplified. Since 7 and 12 have no common factors other than 1, it is already in its simplest form.

Therefore, the sum of $\frac{1}{4} + \frac{2}{6}$ is $\frac{7}{12}$.

To solve the problem of adding the fractions $\frac{4}{8} + \frac{3}{10}$, we follow these steps:

• Step 1: Determine the least common denominator (LCD) for the fractions.
• Step 2: Convert each fraction to have the LCD.
• Step 3: Add the numerators of these converted fractions.

Let's go through each step in detail:

Step 1: Find the least common denominator for the fractions.

The denominators are 8 and 10. The least common multiple of 8 and 10 is 40. So, the LCD is 40.

Step 2: Convert each fraction to an equivalent fraction with a denominator of 40.

For $\frac{4}{8}$: Multiply both the numerator and denominator by 5 to convert it:

$\frac{4 \times 5}{8 \times 5} = \frac{20}{40}$.

For $\frac{3}{10}$: Multiply both the numerator and denominator by 4 to convert it:

$\frac{3 \times 4}{10 \times 4} = \frac{12}{40}$.

Step 3: Add the two fractions with the common denominator:

$\frac{20}{40} + \frac{12}{40} = \frac{20 + 12}{40} = \frac{32}{40}$.

Thus, the sum of the fractions is $\frac{32}{40}$.

Therefore, the solution to the problem is $\frac{32}{40}$.

The problem involves adding the fractions $\frac{1}{3}$ and $\frac{4}{9}$.

Step 1: Identify the Least Common Denominator (LCD).

• The denominators are 3 and 9. The least common multiple of 3 and 9 is 9. Thus, the LCD is 9.

Step 2: Convert the fractions to have the common denominator.

• The fraction $\frac{1}{3}$ must be converted to have the denominator of 9. Multiply both the numerator and denominator by 3:
• $\frac{1}{3} = \frac{1 \times 3}{3 \times 3} = \frac{3}{9}$
• The fraction $\frac{4}{9}$ already has the denominator of 9, so it remains unchanged.

Step 3: Add the equivalent fractions.

• Add the numerators together, keeping the denominator:
• $\frac{3}{9} + \frac{4}{9} = \frac{3+4}{9} = \frac{7}{9}$

Step 4: Simplify the result, if necessary.

• The fraction $\frac{7}{9}$ is already in simplest form.

Therefore, the solution to the problem is $\frac{7}{9}$.

To solve the addition of fractions $\frac{2}{6} + \frac{3}{9}$, we will follow these logical steps:

• Step 1: Find a common denominator.
  The denominators are $6$ and $9$. The least common multiple (LCM) of these numbers is $18$.
• Step 2: Convert each fraction to have the denominator of $18$.
  To convert $\frac{2}{6}$ to a denominator of $18$, multiply both the numerator and the denominator by $3$ (because $6 \times 3 = 18$): $\frac{2}{6} = \frac{2 \times 3}{6 \times 3} = \frac{6}{18}$ To convert $\frac{3}{9}$ to a denominator of $18$, multiply both the numerator and the denominator by $2$ (because $9 \times 2 = 18$): $\frac{3}{9} = \frac{3 \times 2}{9 \times 2} = \frac{6}{18}$
• Step 3: Add the fractions.
  Now that both fractions have the same denominator, add their numerators: $\frac{6}{18} + \frac{6}{18} = \frac{6 + 6}{18} = \frac{12}{18}$
• Step 4: Simplify if possible.
  Check if $\frac{12}{18}$ can be simplified. The greatest common divisor (GCD) of $12$ and $18$ is $6$, so: $\frac{12}{18} = \frac{12 \div 6}{18 \div 6} = \frac{2}{3}$ However, since the original question focused on achieving the fraction with denominator $18$, our final non-simplified answer remains $\frac{12}{18}$.

The final result is that the sum of the fractions is $\frac{12}{18}$.

To solve the fraction addition problem $\frac{2}{4} + \frac{2}{6}$, follow these steps:

• Step 1: Identify the least common denominator (LCD) of the fractions. The denominators are 4 and 6. The factors of 4 are 2 and 2, and the factors of 6 are 2 and 3. The LCD is the smallest number that both denominators divide into, which is 12.

• Step 2: Convert each fraction to an equivalent fraction with the denominator of 12.

• Step 3: For $\frac{2}{4}$:

  • Find the equivalent fraction: Multiply both the numerator and denominator by 3 (since 4 * 3 = 12).

  • The equivalent fraction is $\frac{2 \times 3}{4 \times 3} = \frac{6}{12}$.

• Step 4: For $\frac{2}{6}$:

  • Find the equivalent fraction: Multiply both the numerator and denominator by 2 (since 6 * 2 = 12).

  • The equivalent fraction is $\frac{2 \times 2}{6 \times 2} = \frac{4}{12}$.

• Step 5: Add the new fractions: $\frac{6}{12} + \frac{4}{12} = \frac{10}{12}$.

Therefore, the sum of the fractions is $\boxed{\frac{10}{12}}$.

To solve the problem of adding $\frac{3}{8}$ and $\frac{5}{12}$, follow these steps:

• Step 1: Find the least common multiple (LCM) of the denominators 8 and 12. The LCM of 8 and 12 is 24.
• Step 2: Convert the fractions to have the common denominator 24.
  To convert $\frac{3}{8}$ to a denominator of 24:
  Multiply both the numerator and denominator by 3: $\frac{3 \times 3}{8 \times 3} = \frac{9}{24}$.
• Step 3: Convert $\frac{5}{12}$ to a denominator of 24:
  Multiply both the numerator and denominator by 2: $\frac{5 \times 2}{12 \times 2} = \frac{10}{24}$.
• Step 4: Add the fractions $\frac{9}{24} + \frac{10}{24}$.
  Since they share the same denominator, add the numerators: $9 + 10 = 19$.
• Step 5: The sum is $\frac{19}{24}$. There is no need to simplify further, as 19 and 24 have no common factors other than 1.

Thus, the fraction $\frac{3}{8} + \frac{5}{12}$ simplifies to $\frac{19}{24}$.

To solve this problem, we need to add the fractions $\frac{4}{10}$ and $\frac{5}{12}$ by first finding a common denominator.

Step 1: Find the Least Common Denominator (LCD)

The denominators are $10$ and $12$. The least common multiple of $10$ and $12$ can be determined by prime factorization:

• $10 = 2 \times 5$
• $12 = 2^2 \times 3$

For the LCM, take the highest power of each prime:

• For $2$, take $2^2$
• For $3$, take $3$
• For $5$, take $5$

The LCM is $2^2 \times 3 \times 5 = 60$. Thus, the common denominator is $60$.

Step 2: Convert Fractions to Have the Common Denominator

• Convert $\frac{4}{10}$ to $\frac{?}{60}$.

$\frac{4}{10} = \frac{4 \times 6}{10 \times 6} = \frac{24}{60}$.
• Convert $\frac{5}{12}$ to $\frac{?}{60}$.

$\frac{5}{12} = \frac{5 \times 5}{12 \times 5} = \frac{25}{60}$.

Step 3: Add the Fractions

Add $\frac{24}{60}$ and $\frac{25}{60}$:

$\frac{24}{60} + \frac{25}{60} = \frac{24 + 25}{60} = \frac{49}{60}$.

Therefore, the solution to the problem is $\frac{49}{60}$.

To solve the problem of adding $\frac{1}{4} + \frac{4}{6}$, follow these steps:

• Step 1: Find the Least Common Denominator (LCD):
  The denominators are 4 and 6. The least common multiple of 4 and 6 is 12.
• Step 2: Convert Each Fraction:
  - Convert $\frac{1}{4}$ to a fraction with a denominator of 12:
  $\frac{1}{4} = \frac{1 \times 3}{4 \times 3} = \frac{3}{12}$
  - Convert $\frac{4}{6}$ to a fraction with a denominator of 12:
  $\frac{4}{6} = \frac{4 \times 2}{6 \times 2} = \frac{8}{12}$
• Step 3: Add the Fractions:
  Now, add the fractions: $\frac{3}{12} + \frac{8}{12} = \frac{3 + 8}{12} = \frac{11}{12}$
• Step 4: Simplify the Fraction (if needed):
  The fraction $\frac{11}{12}$ is already in its simplest form.

Therefore, the solution to the problem is $\frac{11}{12}$.

To solve for the sum of $\frac{4}{10} + \frac{2}{6}$, we will proceed with the following steps:

• Step 1: Identify the least common denominator (LCD)
• Step 2: Convert each fraction to an equivalent fraction with this common denominator
• Step 3: Add the numerators

Let's begin:

Step 1: Identify the least common denominator (LCD)
The denominators are 10 and 6. The least common multiple (LCM) of 10 and 6 can be found by evaluating their prime factors:
10 = 2 × 5
6 = 2 × 3
The LCM is found by taking the highest power of each prime that appears:
LCM = 2 × 3 × 5 = 30.
Thus, the common denominator is 30.

Step 2: Convert each fraction to an equivalent fraction with the common denominator of 30
For $\frac{4}{10}$:
Multiply both the numerator and the denominator by 3 to make the denominator 30:
$\frac{4}{10} = \frac{4 \times 3}{10 \times 3} = \frac{12}{30}$.
For $\frac{2}{6}$:
Multiply both the numerator and the denominator by 5 to make the denominator 30:
$\frac{2}{6} = \frac{2 \times 5}{6 \times 5} = \frac{10}{30}$.

Step 3: Add the numerators
Now that the fractions have the same denominator, add the numerators:
$\frac{12}{30} + \frac{10}{30} = \frac{12 + 10}{30} = \frac{22}{30}$.
This fraction cannot be simplified further as 22 and 30 have no common factors besides 1.

Therefore, the sum of $\frac{4}{10} + \frac{2}{6}$ is $\frac{22}{30}$.

To solve this problem, we need to add the fractions $\frac{2}{5}$ and $\frac{3}{10}$.

Firstly, we find a common denominator for the fractions. The denominators are 5 and 10. The least common multiple (LCM) of 5 and 10 is 10.

Next, we convert each fraction to an equivalent fraction with the denominator of 10:

• The fraction $\frac{2}{5}$ is equivalent to $\frac{2 \times 2}{5 \times 2} = \frac{4}{10}$.
• The fraction $\frac{3}{10}$ is already expressed with the denominator of 10, so it remains as $\frac{3}{10}$.

Now, we add both fractions: $\frac{4}{10} + \frac{3}{10} = \frac{4+3}{10} = \frac{7}{10}$.

Therefore, the solution to the exercise is $\frac{7}{10}$.

To solve the addition of these two fractions, we'll proceed as follows:

• Step 1: Determine the least common denominator (LCD) of the fractions.
  The denominators are 4 and 6, and the smallest number that is a multiple of both is 12. Thus, the LCD is 12.
• Step 2: Convert each fraction to an equivalent fraction with the denominator 12.
  - For $\frac{3}{4}$, multiply both numerator and denominator by 3: $\frac{3 \times 3}{4 \times 3} = \frac{9}{12}$.
  - For $\frac{1}{6}$, multiply both numerator and denominator by 2: $\frac{1 \times 2}{6 \times 2} = \frac{2}{12}$.
• Step 3: Add the converted fractions.
  $\frac{9}{12} + \frac{2}{12} = \frac{9 + 2}{12} = \frac{11}{12}$.

Therefore, the solution to the problem is $\frac{11}{12}$.

To solve this problem, we'll follow these steps:

• Step 1: Find the least common multiple (LCM) of the denominators 10 and 4.
• Step 2: Convert both fractions to have the common denominator.
• Step 3: Add the numerators and present the result.

Now, let's work through each step:

Step 1: Find the LCM of 10 and 4. The prime factors of 10 are $2 \times 5$, and for 4, $2^2$. The LCM is $2^2 \times 5 = 20$.

Step 2: Convert the fractions:
$\frac{5}{10}$ can be converted by multiplying both the numerator and the denominator by 2: $\frac{5 \times 2}{10 \times 2} = \frac{10}{20}$.
$\frac{1}{4}$ can be converted by multiplying both the numerator and the denominator by 5: $\frac{1 \times 5}{4 \times 5} = \frac{5}{20}$.

Step 3: Add the fractions:
$\frac{10}{20} + \frac{5}{20} = \frac{10 + 5}{20} = \frac{15}{20}$.

Therefore, the solution to the problem is $\frac{15}{20}$, which matches choice ID 4.

To solve the problem of adding $\frac{2}{4}$ and $\frac{1}{6}$, follow these steps:

Step 1: Identify the least common denominator of the fractions.

The denominators of the fractions are 4 and 6. The least common multiple of 4 and 6 is 12, so 12 is our common denominator.

Step 2: Convert each fraction to an equivalent fraction with the denominator of 12.

• For $\frac{2}{4}$: Multiply both numerator and denominator by 3 to obtain $\frac{6}{12}$. This is because $4 \times 3 = 12$.

• For $\frac{1}{6}$: Multiply both numerator and denominator by 2 to obtain $\frac{2}{12}$. This is because ${6 \times 2 = 12}$.

Step 3: Add the converted fractions.

$\frac{6}{12} + \frac{2}{12} = \frac{6 + 2}{12} = \frac{8}{12}$

Step 4: Simplify the final fraction if possible.

In this case, $\frac{8}{12}$ can be simplified by dividing numerator and denominator by their greatest common divisor, which is 4. Thus, $\frac{8}{12}$ simplifies to $\frac{2}{3}$.

However, as per the problem's required answer, the unsimplified fraction is $\frac{8}{12}$.

Therefore, the solution to the problem is:

$\frac{8}{12}$

To solve this problem, we will follow these steps:

• Step 1: Find the least common denominator of 10 and 6.
• Step 2: Convert both fractions to have this common denominator.
• Step 3: Add the fractions.
• Step 4: Simplify the resulting fraction if possible.

Now, let's work through each step:

Step 1: The least common multiple (LCM) of 10 and 6 is 30. So, our common denominator will be 30.

Step 2: Convert each fraction to have a denominator of 30:
For $\frac{5}{10}$:
$\frac{5}{10} = \frac{5 \times 3}{10 \times 3} = \frac{15}{30}$
For $\frac{1}{6}$:
$\frac{1}{6} = \frac{1 \times 5}{6 \times 5} = \frac{5}{30}$

Step 3: Add the fractions:
$\frac{15}{30} + \frac{5}{30} = \frac{15 + 5}{30} = \frac{20}{30}$

Step 4: Simplify if needed:
The fraction $\frac{20}{30}$ is already simplified to one of the given answer choices with a common denominator, matching one of the options.

Therefore, the solution to the problem is $\frac{20}{30}$.

To solve the problem of adding the fractions $\frac{1}{5}$ and $\frac{7}{10}$, we follow these steps:

• Step 1: Identify the least common multiple (LCM) of the denominators 5 and 10, which is 10.
• Step 2: Convert $\frac{1}{5}$ to a fraction with a denominator of 10. To do this, multiply both the numerator and denominator by 2: $\frac{1}{5} = \frac{1 \times 2}{5 \times 2} = \frac{2}{10}$
• Step 3: Observe that $\frac{7}{10}$ already has the common denominator of 10.
• Step 4: Add the two fractions with a common denominator: $\frac{2}{10} + \frac{7}{10} = \frac{2 + 7}{10} = \frac{9}{10}$

The sum of $\frac{1}{5}$ and $\frac{7}{10}$ is thus $\mathbf{\frac{9}{10}}$.

To find the sum $\frac{1}{4} + \frac{7}{8}$, follow these steps:

• Step 1: Identify the least common denominator (LCD) of the fractions. The denominators 4 and 8 have an LCD of 8.
• Step 2: Convert $\frac{1}{4}$ to an equivalent fraction with a denominator of 8. Multiply both the numerator and the denominator by 2: $\frac{1}{4} = \frac{1 \times 2}{4 \times 2} = \frac{2}{8}$.
• Step 3: The second fraction, $\frac{7}{8}$, already has the correct denominator. Therefore, it remains $\frac{7}{8}$.
• Step 4: Add the numerators of the two fractions: $\frac{2}{8} + \frac{7}{8} = \frac{2+7}{8} = \frac{9}{8}$.

Therefore, the sum of $\frac{1}{4}$ and $\frac{7}{8}$ is $\frac{9}{8}$.

To solve this problem, we'll follow these steps:

• Step 1: Identify the given fractions, $\frac{3}{5}$ and $\frac{3}{10}$.
• Step 2: Find the least common denominator (LCD) of the denominators 5 and 10.
• Step 3: Convert each fraction to have this common denominator.
• Step 4: Add the fractions.

Now, let's work through each step:

Step 1: We have the fractions $\frac{3}{5}$ and $\frac{3}{10}$.

Step 2: Check the denominators. The denominators are 5 and 10. The least common multiple of 5 and 10 is 10. Thus, our common denominator will be 10.

Step 3: Convert each fraction to an equivalent fraction with a denominator of 10:
$\frac{3}{5}$ is equivalent to $\frac{3 \times 2}{5 \times 2} = \frac{6}{10}$ (since $\frac{5}{10}$ must equal 10, multiply both numerator and denominator by 2).

Step 4: The fraction $\frac{3}{10}$ already has the denominator of 10.
Thus, $\frac{3}{5} + \frac{3}{10} = \frac{6}{10} + \frac{3}{10} = \frac{6 + 3}{10} = \frac{9}{10}$.

Therefore, the answer to the problem is $\frac{9}{10}$, which corresponds to choice 1.

To solve this problem, we'll follow these steps:

• Step 1: Identify the denominators of the fractions.
• Step 2: Because the denominators are the same, add the numerators.
• Step 3: Simplify the resulting fraction if necessary.

Now, let's work through each step:
Step 1: Both fractions, $\frac{1}{4}$ and $\frac{3}{4}$, have the same denominator, 4.
Step 2: Since the denominators are the same, we can add the numerators: $1 + 3 = 4$.
Step 3: The resulting fraction is $\frac{4}{4}$, which simplifies to $1$.

Therefore, the solution to the problem is $1$.

To solve the problem of adding $\frac{1}{2}$ and $\frac{1}{6}$, we need to follow these steps:

• Step 1: Determine the least common denominator (LCD).
• Step 2: Convert the fractions to have this common denominator.
• Step 3: Add the fractions.
• Step 4: Simplify the result if necessary.

Step 1: The denominators are 2 and 6. The least common multiple of 2 and 6 is 6.

Step 2: We convert each fraction:
- Convert $\frac{1}{2}$ to a denominator of 6: $\frac{1}{2} = \frac{1 \times 3}{2 \times 3} = \frac{3}{6}$.
- The fraction $\frac{1}{6}$ already has the denominator 6.

Step 3: Add the fractions with common denominators:
$\frac{3}{6} + \frac{1}{6} = \frac{3 + 1}{6} = \frac{4}{6}.$

Step 4: Simplify the fraction $\frac{4}{6}$.
The greatest common divisor of 4 and 6 is 2, so divide both the numerator and the denominator by 2:
$\frac{4}{6} = \frac{4 \div 2}{6 \div 2} = \frac{2}{3}.$

Therefore, the solution to the problem is $\frac{2}{3}$.

To solve this problem, we will perform the following steps:

• Step 1: Find the Least Common Multiple (LCM) of the denominators 3 and 9.
• Step 2: Convert both fractions to have a common denominator.
• Step 3: Add the numerators of the converted fractions and write the result over the common denominator.
• Step 4: Simplify the resultant fraction if needed.

Let's work through each step:

Step 1:
The denominators of our fractions are 3 and 9. The LCM of 3 and 9 is 9, since 9 is the smallest number that both 3 and 9 divide evenly into.

Step 2:
Convert each fraction to have a denominator of 9.

- For $\frac{2}{3}$, multiply both the numerator and denominator by 3 (because $\frac{9}{3} = 3$):
$\frac{2}{3} = \frac{2 \times 3}{3 \times 3} = \frac{6}{9}$

- The second fraction $\frac{7}{9}$ already has a denominator of 9, so it remains the same:
$\frac{7}{9}$

Step 3:
Add the two fractions:
$\frac{6}{9} + \frac{7}{9} = \frac{6 + 7}{9} = \frac{13}{9}$

Step 4:
The fraction $\frac{13}{9}$ is in its simplest form because 13 is a prime number and does not divide evenly into 9.

Therefore, the solution to the problem is $\frac{13}{9}$.