To add fractions, we must find the common denominator simplifying, expanding, or multiplying the denominators.

Then, you only need to add the numerators to get the result.

Question Types:

To add fractions, we must find the common denominator simplifying, expanding, or multiplying the denominators.

Then, you only need to add the numerators to get the result.

Question 1

\( \frac{5+3-2}{3}= \)

Question 2

\( \frac{5}{6}x+\frac{7}{8}x+\frac{2}{4}x= \)

Question 3

\( \frac{4}{8}+\frac{4}{10}= \)

Question 4

\( \)\( \frac{4}{5}+\frac{1}{5}= \)

Question 5

\( \frac{5}{9}+\frac{4}{9}= \)

$\frac{5+3-2}{3}=$

Let's focus on the fraction of the fraction.

According to the order of operations rules, we'll solve from left to right, since it only contains addition and subtraction operations:

$5+3=8$

$8-2=6$

Now we'll get the fraction:

$\frac{6}{3}$

We'll reduce the numerator and denominator by 3 and get:

$\frac{2}{1}=2$

$2$

$\frac{5}{6}x+\frac{7}{8}x+\frac{2}{4}x=$

First, let's find a common denominator for 4, 8, and 6: it's 24.

Now, we'll multiply each fraction by the appropriate number to get:

$\frac{5\times4}{6\times4}x+\frac{7\times3}{8\times3}x+\frac{2\times6}{4\times6}x=$

Let's solve the multiplication exercises in the numerator and denominator:

$\frac{20}{24}x+\frac{21}{24}x+\frac{12}{24}x=$

We'll connect all the numerators:

$\frac{20+21+12}{24}x=\frac{41+12}{24}x=\frac{53}{24}x$

Let's break down the numerator into a smaller addition exercise:

$\frac{48+5}{24}=\frac{48}{24}+\frac{5}{24}=2+\frac{5}{24}=2\frac{5}{24}x$

$2\frac{5}{24}x$

$\frac{4}{8}+\frac{4}{10}=$

Let's try to find the lowest common multiple between 8 and 10

To find the lowest common multiple, we need to find a number that is divisible by both 8 and 10

In this case, the lowest common multiple is 40

Now, let's multiply each number in the appropriate multiples to reach the number 40

We will multiply the first number by 5

We will multiply the second number by 4

$\frac{4\times5}{8\times5}+\frac{4\times4}{10\times4}=\frac{20}{40}+\frac{16}{40}$

Now let's calculate:

$\frac{20+16}{40}=\frac{36}{40}$

$\frac{36}{40}$

$\frac{4}{5}+\frac{1}{5}=$

$1$

$\frac{5}{9}+\frac{4}{9}=$

$1$

Question 1

\( \frac{5}{8}+\frac{1}{8}= \)

Question 2

\( \frac{3}{8}+\frac{4}{8}= \)

Question 3

Solve the following exercise:

\( \frac{1}{2}+\frac{1}{2}=\text{?} \)

Question 4

\( \frac{1}{2}+\frac{1}{2}= \)

Question 5

Solve the following exercise:

\( \frac{1}{4}+\frac{1}{4}=\text{?} \)

$\frac{5}{8}+\frac{1}{8}=$

$\frac{6}{8}$

$\frac{3}{8}+\frac{4}{8}=$

$\frac{7}{8}$

Solve the following exercise:

$\frac{1}{2}+\frac{1}{2}=\text{?}$

1

$\frac{1}{2}+\frac{1}{2}=$

$1$

Solve the following exercise:

$\frac{1}{4}+\frac{1}{4}=\text{?}$

$\frac{2}{4}$

Question 1

\( \frac{1}{4}+\frac{3}{4}= \)

Question 2

\( \frac{2}{4}+\frac{1}{4}= \)\( \)

Question 3

\( \frac{2}{5}+\frac{1}{5}= \)

Question 4

\( \frac{2}{6}+\frac{3}{6}= \)

Question 5

\( \frac{2}{7}+\frac{1}{7}= \)

$\frac{1}{4}+\frac{3}{4}=$

$1$

$\frac{2}{4}+\frac{1}{4}=$

$\frac{3}{4}$

$\frac{2}{5}+\frac{1}{5}=$

$\frac{3}{5}$

$\frac{2}{6}+\frac{3}{6}=$

$\frac{5}{6}$

$\frac{2}{7}+\frac{1}{7}=$

$\frac{3}{7}$