Examples with solutions for The function y=ax²+bx+c: Matching parameters

Exercise #1

y=x2 y=x^2

Video Solution

Step-by-Step Solution

To solve this problem, let's follow these steps:

  • Step 1: Recognize the standard form of a quadratic equation.
  • Step 2: Match the given function to the standard form.
  • Step 3: Identify each coefficient a a , b b , and c c .

Now, let's work through these steps:

Step 1: The standard form of a quadratic function is y=ax2+bx+c y = ax^2 + bx + c . Our goal is to identify a a , b b , and c c .

Step 2: We are given the function y=x2 y = x^2 . This can be aligned with the standard form as y=1x2+0x+0 y = 1 \cdot x^2 + 0 \cdot x + 0 .

Step 3: By comparing the given function y=x2 y = x^2 with the standard form, we can deduce:
- The coefficient of x2 x^2 is 1, so a=1 a = 1 .
- The linear term coefficient is missing, which implies b=0 b = 0 .
- There is no constant term, so c=0 c = 0 .

Therefore, the coefficients are a=1,b=0,c=0 a = 1, b = 0, c = 0 , corresponding to choice 1.

Answer

a=1,b=0,c=0 a=1,b=0,c=0

Exercise #2

y=x2+10x y=x^2+10x

Video Solution

Step-by-Step Solution

Here we have a quadratic equation.

A quadratic equation is always constructed like this:

 

y=ax2+bx+c y = ax²+bx+c

 

Where a, b, and c are generally already known to us, and the X and Y points need to be discovered.

Firstly, it seems that in this formula we do not have the C,

Therefore, we understand it is equal to 0.

c=0 c = 0

 

a is the coefficient of X², here it does not have a coefficient, therefore

a=1 a = 1

 

b=10 b= 10

is the number that comes before the X that is not squared.

 

Answer

a=1,b=10,c=0 a=1,b=10,c=0

Exercise #3

y=x26x+4 y=x^2-6x+4

Video Solution

Step-by-Step Solution

To solve this problem, we'll clearly delineate the given expression and compare it to the standard quadratic form:

  • Step 1: Recognize the standard form of a quadratic equation as y=ax2+bx+c y = ax^2 + bx + c .
  • Step 2: Compare the given equation y=x26x+4 y = x^2 - 6x + 4 to the standard form.
  • Step 3: Identify coefficients:
    - The coefficient of x2 x^2 is a=1 a = 1 .
    - The coefficient of x x is b=6 b = -6 .
    - The constant term is c=4 c = 4 .

Therefore, the coefficients for the quadratic function y=x26x+4 y = x^2 - 6x + 4 are a=1 a = 1 , b=6 b = -6 , and c=4 c = 4 .

Among the provided choices, choice 3: a=1,b=6,c=4 a=1,b=-6,c=4 is the correct one.

Answer

a=1,b=6,c=4 a=1,b=-6,c=4

Exercise #4

y=2x25x+6 y=2x^2-5x+6

Video Solution

Step-by-Step Solution

In fact, a quadratic equation is composed as follows:

y = ax²-bx-c

 

That is,

a is the coefficient of x², in this case 2.
b is the coefficient of x, in this case 5.
And c is the number without a variable at the end, in this case 6.

Answer

a=2,b=5,c=6 a=2,b=-5,c=6

Exercise #5

y=2x23x6 y=2x^2-3x-6

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Identify the given quadratic function.
  • Match it with the standard form of a quadratic equation y=ax2+bx+cy = ax^2 + bx + c.
  • Extract the values of aa, bb, and cc directly from the comparison.

Now, let's work through each step:
Step 1: The given quadratic function is y=2x23x6y = 2x^2 - 3x - 6.
Step 2: The standard form of a quadratic equation is y=ax2+bx+cy = ax^2 + bx + c.
Step 3: By matching the given quadratic function with the standard form:

- The coefficient of x2x^2 is 22, so a=2a = 2.
- The coefficient of xx is 3-3, so b=3b = -3.
- The constant term is 6-6, so c=6c = -6.

Therefore, the solution to the problem is a=2a = 2, b=3b = -3, c=6c = -6.

Answer

a=2,b=3,c=6 a=2,b=-3,c=-6

Exercise #6

y=2x2+3x+10 y=-2x^2+3x+10

Video Solution

Step-by-Step Solution

Let's determine the coefficients for the quadratic function given by y=2x2+3x+10 y = -2x^2 + 3x + 10 .

  • Step 1: Identify a a .
    The coefficient of x2 x^2 is 2-2. Thus, a=2 a = -2 .
  • Step 2: Identify b b .
    The coefficient of x x is 33. Thus, b=3 b = 3 .
  • Step 3: Identify c c .
    The constant term is 1010. Thus, c=10 c = 10 .

Comparing these coefficients to the provided choices, the correct answer is:

a=2,b=3,c=10 a = -2, b = 3, c = 10 .

Therefore, the correct choice is Choice 4.

Answer

a=2,b=3,c=10 a=-2,b=3,c=10

Exercise #7

y=3x2+4x+5 y=3x^2+4x+5

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the given quadratic function.
  • Step 2: Compare it to the standard form y=ax2+bx+c y = ax^2 + bx + c .
  • Step 3: Determine the values of a a , b b , and c c .

Now, let's work through each step:

Step 1: The problem gives us the quadratic function y=3x2+4x+5 y = 3x^2 + 4x + 5 .

Step 2: The standard form of a quadratic function is y=ax2+bx+c y = ax^2 + bx + c .

Step 3: By comparing y=3x2+4x+5 y = 3x^2 + 4x + 5 with y=ax2+bx+c y = ax^2 + bx + c , we find:
- The coefficient of x2 x^2 is a=3 a = 3 .
- The coefficient of x x is b=4 b = 4 .
- The constant term is c=5 c = 5 .

Therefore, the solution to the problem is a=3,b=4,c=5 a = 3, b = 4, c = 5 .

This matches choice 2, which states: a=3,b=4,c=5 a = 3, b = 4, c = 5 .

Answer

a=3,b=4,c=5 a=3,b=4,c=5

Exercise #8

y=x2+x+5 y=x^2+x+5

Video Solution

Step-by-Step Solution

To solve this problem, we will identify the parameters of the given quadratic function step-by-step:

  • Step 1: Define the problem statement: We have y=x2+x+5 y = x^2 + x + 5 .
  • Step 2: Identify the standard form of a quadratic function, which is y=ax2+bx+c y = ax^2 + bx + c .
  • Step 3: Compare the given quadratic expression with the standard form to identify the coefficients.

Now, let's analyze the quadratic function provided:

From the given expression y=x2+x+5 y = x^2 + x + 5 :
- The coefficient of x2 x^2 is 1 1 , so a=1 a = 1 .
- The coefficient of x x is 1 1 , so b=1 b = 1 .
- The constant term is 5 5 , so c=5 c = 5 .

Therefore, the parameters of the quadratic function are a=1 a = 1 , b=1 b = 1 , and c=5 c = 5 .

Consequently, the correct choice from the provided options is (a=1,b=1,c=5) (a = 1, b = 1, c = 5) .

Answer

a=1,b=1,c=5 a=1,b=1,c=5

Exercise #9

y=x2+x+5 y=-x^2+x+5

Video Solution

Step-by-Step Solution

To solve the problem of identifying the coefficients in the quadratic function y=x2+x+5 y = -x^2 + x + 5 , we follow these steps:

  • Step 1: Write down the general form of a quadratic equation: y=ax2+bx+c y = ax^2 + bx + c .

  • Step 2: Compare the given equation y=x2+x+5 y = -x^2 + x + 5 to the general form.

  • Step 3: Identify the value of each coefficient:

    • The coefficient of x2 x^2 is 1-1, so a=1 a = -1 .

    • The coefficient of x x is +1+1, so b=1 b = 1 .

    • The constant term is +5+5, so c=5 c = 5 .

Therefore, the parameters of the quadratic function are a=1 a = -1 , b=1 b = 1 , and c=5 c = 5 .

This matches choice 2, confirming the parameters in the quadratic function.

Final Answer: a=1,b=1,c=5 a=-1, b=1, c=5 .

Answer

a=1,b=1,c=5 a=-1,b=1,c=5

Exercise #10

y=4+3x2x y=4+3x^2-x

Video Solution

Step-by-Step Solution

To solve this problem, we will match the given quadratic equation with its standard form:

  • Step 1: Identify the standard quadratic form as y=ax2+bx+cy = ax^2 + bx + c.
  • Step 2: Compare with given equation y=4+3x2xy = 4 + 3x^2 - x.
  • Step 3: Determine the coefficients by arranging the equation in standard form.

Let's now perform the steps:

Step 1: The standard quadratic form is y=ax2+bx+cy = ax^2 + bx + c.

Step 2: The given equation is y=4+3x2xy = 4 + 3x^2 - x.

Step 3: Rearrange the given equation to match the standard form:

y=3x2x+4y = 3x^2 - x + 4.

Now, directly compare:

a=3a = 3

b=1b = -1

c=4c = 4

Therefore, the coefficients are correctly identified as a=3,b=1, a=3, b=-1, and c=4 c=4 .

The correct answer is: a=3,b=1,c=4 a=3, b=-1, c=4 .

Answer

a=3,b=1,c=4 a=3,b=-1,c=4

Exercise #11

y=3x2+45x y=3x^2+4-5x

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Rearrange the given quadratic function into the standard form.
  • Step 2: Identify the coefficients by comparing them with the standard quadratic function.

Now let's work through each step:

Step 1: The given quadratic is y=3x2+45x y = 3x^2 + 4 - 5x . Rearrange this function to align terms with their degrees:
y=3x25x+4 y = 3x^2 - 5x + 4 .

Step 2: Compare this with the standard quadratic form y=ax2+bx+c y = ax^2 + bx + c , where:
a=3 a = 3 (the coefficient of x2x^2),
b=5 b = -5 (the coefficient of xx),
c=4 c = 4 (the constant term).

Therefore, the correct choice is a=3,b=5,c=4 a = 3, b = -5, c = 4 .

Answer

a=3,b=5,c=4 a=3,b=-5,c=4

Exercise #12

y=4x23x y=-4x^2-3x

Video Solution

Step-by-Step Solution

To solve this problem, we'll identify the parameters a a , b b , and c c in the quadratic function.

The quadratic equation provided is y=4x23x y = -4x^2 - 3x . To match this equation with the standard quadratic form y=ax2+bx+c y = ax^2 + bx + c , we must determine the values of a a , b b , and c c .

  • Step 1: Identify a a . The coefficient of x2 x^2 in the given equation is 4-4. Thus, a=4 a = -4 .
  • Step 2: Identify b b . The coefficient of x x in the given equation is 3-3. Thus, b=3 b = -3 .
  • Step 3: Identify c c . The constant term (the term not involving x x ) does not appear in the equation, which means c=0 c = 0 .

Therefore, the values of the parameters are a=4 a = -4 , b=3 b = -3 , and c=0 c = 0 . This matches with choice 3 in the provided options.

The correct answer is a=4,b=3,c=0 a = -4, b = -3, c = 0 .

Answer

a=4,b=3,c=0 a=-4,b=-3,c=0

Exercise #13

y=x2+3x+40 y=-x^2+3x+40

Video Solution

Step-by-Step Solution

To solve this problem, we will follow these steps:

  • Step 1: Identify the given quadratic equation and its form.
  • Step 2: Directly match the coefficients of the given equation to the standard form y=ax2+bx+c y = ax^2 + bx + c .
  • Step 3: Compare with the provided choices and select the one that matches.

Now, let's work through each step:
Step 1: The given quadratic equation is y=x2+3x+40 y = -x^2 + 3x + 40 . This matches the form y=ax2+bx+c y = ax^2 + bx + c .

Step 2: By comparing the given equation to the standard form:
- The coefficient a a is the coefficient of x2 x^2 , which is 1-1.
- The coefficient b b is the coefficient of x x , which is 3 3 .
- The coefficient c c is the constant term, which is 40 40 .

Step 3: From the analysis, we identify a=1 a = -1 , b=3 b = 3 , c=40 c = 40 . We compare these with the provided choices.
The correct answer is: a=1,b=3,c=40 a=-1,b=3,c=40

Therefore, the solution to the problem matches choice 4.

Answer

a=1,b=3,c=40 a=-1,b=3,c=40

Exercise #14

y=6x+3x24 y=6x+3x^2-4

Video Solution

Step-by-Step Solution

To solve this problem, we'll proceed with the following steps:

  • Step 1: Rewrite the given quadratic function y=6x+3x24 y = 6x + 3x^2 - 4 .
  • Step 2: Compare the equation to the standard form of a quadratic equation y=ax2+bx+c y = ax^2 + bx + c .
  • Step 3: Identify and assign the values of coefficients a a , b b , and c c .

Now, let's execute these steps:

Step 1: The given function is already y=6x+3x24 y = 6x + 3x^2 - 4 .

Step 2: The standard form of a quadratic equation is y=ax2+bx+c y = ax^2 + bx + c .

Step 3: Upon comparison, we can observe:

  • The coefficient of x2 x^2 is 3, so a=3 a = 3 .
  • The coefficient of x x is 6, so b=6 b = 6 .
  • The constant term is 4-4, so c=4 c = -4 .

Therefore, the solution is a=3,b=6,c=4 a=3, b=6, c=-4 . This corresponds to choice 1.

Answer

a=3,b=6,c=4 a=3,b=6,c=-4

Exercise #15

y=5x2+x y=-5x^2+x

Video Solution

Step-by-Step Solution

To solve this problem, let's follow these steps:

  • Step 1: Write down the provided quadratic function and the standard form for comparison.
  • Step 2: Identify the coefficients aa, bb, and cc by matching terms.
  • Step 3: Match the identified coefficients with the given answer choices.

Step 1: The given quadratic function is y=5x2+xy = -5x^2 + x, and we will compare it to the standard quadratic form y=ax2+bx+cy = ax^2 + bx + c.

Step 2: By comparing the terms, we identify:

  • a=5a = -5 from the coefficient of x2x^2
  • b=1b = 1 from the coefficient of xx
  • c=0c = 0 since there is no constant term present

Therefore, from the given choices, the correct parameter set is identified as a=5a = -5, b=1b = 1, and c=0c = 0.

Thus, the correct answer is:

a=5,b=1,c=0 a=-5,b=1,c=0

Answer

a=5,b=1,c=0 a=-5,b=1,c=0

Exercise #16

y=x3x2 y=-x-3x^2

Video Solution

Step-by-Step Solution

To solve this problem, we will write the given function in standard form:

The function provided is y=x3x2 y = -x - 3x^2 . Our goal is to express it in the standard form y=ax2+bx+c y = ax^2 + bx + c .

  • Step 1: Reorder the terms: Write the quadratic term first, followed by the linear term and then the constant.

Thus, the given function becomes y=3x2x+0 y = -3x^2 - x + 0 .

  • Step 2: Identify the coefficients a a , b b , and c c :

From the expression y=3x2x+0 y = -3x^2 - x + 0 , we observe:

  • The coefficient a a is -3 (from the term 3x2-3x^2).

  • The coefficient b b is -1 (from the term x-x).

  • The coefficient c c is 0 (as there is no constant term).

Therefore, the correct choice displaying these coefficients is a=3 a = -3 , b=1 b = -1 , and c=0 c = 0 , which corresponds to choice 4.

Thus, the solution is:

a=3,b=1,c=0 a = -3, b = -1, c = 0

Answer

a=3,b=1,c=0 a=-3,b=-1,c=0

Exercise #17

y=6+x2+6x y=-6+x^2+6x

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the given equation
  • Step 2: Reorganize the equation to match the standard form of a quadratic equation
  • Step 3: Compare the terms to determine the coefficients a a , b b , and c c

Now, let's work through each step:
Step 1: The provided equation is y=6+x2+6x y = -6 + x^2 + 6x .
Step 2: Rearrange the terms to match the standard form y=ax2+bx+c y = ax^2 + bx + c . This gives us y=x2+6x6 y = x^2 + 6x - 6 .
Step 3: Compare the terms:
The coefficient of x2 x^2 (the squared term) is a a . Hence, a=1 a = 1 .
The coefficient of x x (the linear term) is b b . Hence, b=6 b = 6 .
The constant term is c c . Hence, c=6 c = -6 .

Therefore, the solution to the problem is that the coefficients are a=1,b=6,c=6 a = 1, b = 6, c = -6 .

Answer

a=1,b=6,c=6 a=1,b=6,c=-6

Exercise #18

y=3x4x2+3 y=-3x-4x^2+3

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify and write the standard form of a quadratic equation y=ax2+bx+c y = ax^2 + bx + c .
  • Step 2: Compare the given function with the standard form to find the coefficients a a , b b , and c c .

Now, let's work through each step:

Step 1: The standard form of a quadratic equation is y=ax2+bx+c y = ax^2 + bx + c .

Step 2: Comparing the given equation y=3x4x2+3 y = -3x - 4x^2 + 3 with the standard form:

  • The coefficient of x2 x^2 is 4-4, thus a=4 a = -4 .
  • The coefficient of x x is 3-3, thus b=3 b = -3 .
  • The constant term is 33, thus c=3 c = 3 .

Therefore, the coefficients are a=4 a = -4 , b=3 b = -3 , c=3 c = 3 .

The correct option is: : a=4,b=3,c=3 a=-4,b=-3,c=3

Answer

a=4,b=3,c=3 a=-4,b=-3,c=3

Exercise #19

y=5+x2 y=-5+x^2

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Express the equation in a standard quadratic form y=ax2+bx+c y = ax^2 + bx + c
  • Step 2: Identify the coefficients a a , b b , and the constant term c c by comparing the forms
  • Step 3: Select the corresponding answer choice based on the comparison

Now, let's work through each step:

Step 1: The given equation is y=5+x2 y = -5 + x^2 . We can rewrite this as y=x2+0x5 y = x^2 + 0x - 5 to match the standard quadratic form y=ax2+bx+c y = ax^2 + bx + c .

Step 2: By comparing y=x2+0x5 y = x^2 + 0x - 5 directly with y=ax2+bx+c y = ax^2 + bx + c , we can identify:

  • The coefficient of x2 x^2 is a=1 a = 1 .
  • The coefficient of x x is b=0 b = 0 .
  • The constant term is c=5 c = -5 .

Step 3: Among the provided answer choices, we find that the parameters a=1 a = 1 , b=0 b = 0 , and c=5 c = -5 match the choice:

a=1,b=0,c=5 a = 1, b = 0, c = -5

Therefore, the solution to the problem is a=1,b=0,c=5 a = 1, b = 0, c = -5 .

Answer

a=1,b=0,c=5 a=1,b=0,c=-5

Exercise #20

y=2x2+3 y=2x^2+3

Video Solution

Step-by-Step Solution

To solve this problem, we will follow these steps:

  • Step 1: Identify each term in the given function y=2x2+3y = 2x^2 + 3.
  • Step 2: Compare the equation to the standard quadratic form y=ax2+bx+cy = ax^2 + bx + c.
  • Step 3: Determine the coefficients aa, bb, and cc.
  • Step 4: Match these coefficients to the correct multiple-choice option.

Step 1: The given function is y=2x2+3y = 2x^2 + 3. There is no xx term present.

Step 2: Compare this with the standard form y=ax2+bx+cy = ax^2 + bx + c:

  • The coefficient of x2x^2 is a=2a = 2.
  • The coefficient of xx is b=0b = 0 because there is no xx term.
  • The constant term is c=3c = 3.

Step 3: Therefore, the coefficients are a=2a = 2, b=0b = 0, and c=3c = 3.

Step 4: Review the multiple-choice options provided:

  • Choice 1: a=0a = 0, b=2b = 2, c=3c = 3
  • Choice 2: a=0a = 0, b=3b = 3, c=2c = 2
  • Choice 3: a=2a = 2, b=0b = 0, c=3c = 3
  • Choice 4: a=3a = 3, b=0b = 0, c=2c = 2

The correct choice is Choice 3: a=2a = 2, b=0b = 0, c=3c = 3.

Therefore, the solution to the problem is the values a=2a = 2, b=0b = 0, c=3c = 3 which correspond to choice 3.

Answer

a=2,b=0,c=3 a=2,b=0,c=3

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