Quadratic Function Practice Problems and Solutions

Master quadratic functions with step-by-step practice problems. Learn standard form, vertex form, factored form, and solving techniques with detailed solutions.

📚Master Quadratic Functions Through Practice
  • Identify quadratic functions in standard form f(x) = ax² + bx + c
  • Convert between standard, vertex, and factored forms of quadratic functions
  • Find zeros and roots using factoring and quadratic formula methods
  • Graph parabolas and determine vertex, axis of symmetry, and transformations
  • Solve quadratic inequalities and interpret solution sets graphically
  • Apply quadratic functions to real-world word problems and systems

Understanding The Quadratic Function

Complete explanation with examples

f(x)=ax2+bx+c f\left(x\right)=ax^2+bx+c

Where a0 a\ne0 , since if the coefficient a a does not appear then it would not be a quadratic function.

The graph of a quadratic function will always be a parabola.

Example 1:

f(x)=8x22x+4 f\left(x\right)=8x^2-2x+4

It is a quadratic or second-degree function because its largest exponent is 2 2 .

Example 2:

f(x)=7x3+6x2+2x1 f\left(x\right)=-7x^3+6x^2+2x-1

This is not a second-degree function because, although it has an exponent 2 2 , its largest exponent is 3 3 .

Quadratic function

The equation of the basic quadratic function is: y=ax2+bx+cy=ax^2+bx+c

This way of writing them is called the general form of a second-degree function, where:

ax2 ax^2 is called the squared term, quadratic term, or second-degree term.

a a is the coefficient of the quadratic term.

bx bx is called the linear term or first-degree term.

b b is the coefficient of the linear term.

c c is the constant term.

x x is called the unknown of the function and represents the number or numbers that make the function or in this case the equation true.

Example:

f(x)=3x25x+2 f\left(x\right)=3x^2-5x+2

a=3 a=3 , b=5 b=-5 and c=2 c=2

We must remember that for an equation to be of second degree, a a must always be different from zero.


Detailed explanation

Practice The Quadratic Function

Test your knowledge with 17 quizzes

Identify the coefficients based on the following equation

\( y=-3x^2-4 \)

Examples with solutions for The Quadratic Function

Step-by-step solutions included
Exercise #1

What is the value of the coefficient c c in the equation below?

3x2+5x 3x^2+5x

Step-by-Step Solution

The quadratic equation of the given problem has already been arranged (that is, all the terms are on one side and 0 is on the other side) thus we can approach the question as follows:

In the problem, the question was asked: what is the value of the coefficientc c in the equation?

Let's remember the definition of a coefficient when solving a quadratic equation as well as the formula for the roots:

The rule says that the roots of an equation of the form

ax2+bx+c=0 ax^2+bx+c=0 are:

x1,2=b±b24ac2a x_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

That is the coefficient
c c is the free term - and as such the coefficient of the term is raised to the power of zero -x0 x^0 (Any number other than zero raised to the power of zero equals 1:

x0=1 x^0=1 )

Next we examine the equation of the given problem:

3x2+5x=0 3x^2+5x=0 Note that there is no free term in the equation, that is, the numerical value of the free term is 0, in fact the equation can be written as follows:

3x2+5x+0=0 3x^2+5x+0=0 and therefore the value of the coefficientc c is 0.

Hence the correct answer is option c.

Answer:

0

Video Solution
Exercise #2

What is the value of the coefficient b b in the equation below?

3x2+8x5 3x^2+8x-5

Step-by-Step Solution

The quadratic equation of the given problem is already arranged (that is, all the terms are found on one side and the 0 on the other side), thus we approach the given problem as follows;

In the problem, the question was asked: what is the value of the coefficientb b in the equation?

Let's remember the definitions of coefficients when solving a quadratic equation as well as the formula for the roots:

The rule says that the roots of an equation of the form

ax2+bx+c=0 ax^2+bx+c=0 are :

x1,2=b±b24ac2a x_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

That is the coefficientb b is the coefficient of the term in the first power -x x We then examine the equation of the given problem:

3x2+8x5=0 3x^2+8x-5 =0 That is, the number that multiplies

x x is

8 8 Consequently we are able to identify b, which is the coefficient of the term in the first power, as the number8 8 ,

Thus the correct answer is option d.

Answer:

8

Video Solution
Exercise #3

What is the value of the coefficient c c in the equation below?

4x2+9x2 4x^2+9x-2

Step-by-Step Solution

The quadratic equation is given as 4x2+9x2 4x^2 + 9x - 2 . This equation is in the standard form of a quadratic equation, which is ax2+bx+c ax^2 + bx + c , where a a , b b , and c c are coefficients.

  • The term 4x2 4x^2 indicates that the coefficient a=4 a = 4 .
  • The term 9x 9x indicates that the coefficient b=9 b = 9 .
  • The constant term 2-2 indicates that the coefficient c=2 c = -2 .

From this analysis, we can see that the coefficient c c is 2-2.

Therefore, the value of the coefficient c c in the equation is 2-2.

Answer:

-2

Video Solution
Exercise #4

Identify the coefficients based on the following equation

y=5x2 y=-5x^2

Step-by-Step Solution

To solve the problem, we'll identify the parameters a a , b b , and c c from the given quadratic function:

  • **Step 1**: Compare the given equation y=5x2 y = -5x^2 with the general quadratic form y=ax2+bx+c y = ax^2 + bx + c .
  • **Step 2**: Note that the coefficient of x2 x^2 is 5-5, hence a=5 a = -5 .
  • **Step 3**: Since there is no x x term, b=0 b = 0 .
  • **Step 4**: Since there is no constant term, c=0 c = 0 .

After identifying the parameters, we conclude:

The parameters for the quadratic function are a=5 a = -5 , b=0 b = 0 , c=0 c = 0 . Therefore, the correct choice is:

The correct answer is a=5,b=0,c=0 a = -5, b = 0, c = 0 .

Answer:

a=5,b=0,c=0 a=-5,b=0,c=0

Video Solution
Exercise #5

y=2x2+3 y=2x^2+3

Step-by-Step Solution

To solve this problem, we will follow these steps:

  • Step 1: Identify each term in the given function y=2x2+3y = 2x^2 + 3.
  • Step 2: Compare the equation to the standard quadratic form y=ax2+bx+cy = ax^2 + bx + c.
  • Step 3: Determine the coefficients aa, bb, and cc.
  • Step 4: Match these coefficients to the correct multiple-choice option.

Step 1: The given function is y=2x2+3y = 2x^2 + 3. There is no xx term present.

Step 2: Compare this with the standard form y=ax2+bx+cy = ax^2 + bx + c:

  • The coefficient of x2x^2 is a=2a = 2.
  • The coefficient of xx is b=0b = 0 because there is no xx term.
  • The constant term is c=3c = 3.

Step 3: Therefore, the coefficients are a=2a = 2, b=0b = 0, and c=3c = 3.

Step 4: Review the multiple-choice options provided:

  • Choice 1: a=0a = 0, b=2b = 2, c=3c = 3
  • Choice 2: a=0a = 0, b=3b = 3, c=2c = 2
  • Choice 3: a=2a = 2, b=0b = 0, c=3c = 3
  • Choice 4: a=3a = 3, b=0b = 0, c=2c = 2

The correct choice is Choice 3: a=2a = 2, b=0b = 0, c=3c = 3.

Therefore, the solution to the problem is the values a=2a = 2, b=0b = 0, c=3c = 3 which correspond to choice 3.

Answer:

a=2,b=0,c=3 a=2,b=0,c=3

Video Solution

Frequently Asked Questions

What is the standard form of a quadratic function?

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The standard form of a quadratic function is f(x) = ax² + bx + c, where a ≠ 0. The term ax² is the quadratic term, bx is the linear term, and c is the constant term.

How do you find the vertex of a quadratic function?

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You can find the vertex using the vertex form f(x) = a(x - h)² + k, where (h, k) is the vertex. Alternatively, use h = -b/(2a) to find the x-coordinate, then substitute to find the y-coordinate.

What's the difference between complete and incomplete quadratic functions?

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A complete quadratic function has all three terms: ax², bx, and c. An incomplete quadratic function is missing either the linear term (b = 0), constant term (c = 0), or both, but must always have the quadratic term ax².

How do you solve quadratic equations using the quadratic formula?

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Use the quadratic formula: x = (-b ± √(b² - 4ac))/(2a). First identify coefficients a, b, and c from ax² + bx + c = 0, then substitute into the formula to find the roots.

What does the discriminant tell you about quadratic solutions?

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The discriminant (b² - 4ac) determines the number of solutions: • If positive: two real solutions • If zero: one real solution • If negative: no real solutions (two complex solutions)

How do parabola transformations work in quadratic functions?

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Transformations follow these patterns: y = x² + k (vertical shift k units), y = (x - h)² (horizontal shift h units), and y = (x - h)² + k (combined horizontal and vertical shifts).

When should you use factoring vs quadratic formula?

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Use factoring when the quadratic easily factors into perfect squares or simple binomials. Use the quadratic formula for complex expressions, decimal coefficients, or when factoring isn't obvious.

How do you solve systems of quadratic equations?

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For two quadratic equations, use substitution or elimination methods. Graphically, solutions are intersection points of two parabolas. Systems can have 0, 1, or 2 solutions depending on how the parabolas intersect.

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