To solve the problem 231ββ132β, we'll perform the following steps:
- Step 1: Subtract the integer parts: 2β1=1.
- Step 2: Subtract the fractional parts: 31ββ32β.
To calculate 31ββ32β:
Since the fractions have a common denominator, subtract only the numerators:
1β2=β1.
Therefore, 31ββ32β=β31β.
Now combine the results:
The subtraction results in 1β31β.
To simplify, note 1=33β.
Thus, 1β31β=33ββ31β=32β.
Therefore, the solution to 231ββ132β is 32β.