The first step:
We will convert the mixed numbers into equivalent fractions - fractions with numerator and denominator without whole numbers.
The second step:
Find a common denominator (usually by multiplying the denominators).
The third step:
We will only add or subtract the numerators. The denominator will be written once in the final result.
\( \frac{1}{2}+3\frac{1}{2}+4\frac{2}{4}= \)
\( 7\frac{5}{6}+6\frac{2}{3}+\frac{1}{3}= \)
\( \frac{1}{3}+\frac{2}{3}+2\frac{3}{4}= \)
\( \frac{6}{7}x+\frac{8}{7}x+3\frac{2}{3}x= \)
\( 5\frac{2}{5}+2\frac{1}{5}= \)
According to the order of operations, we will solve the exercise from left to right.
Let's note that in the first addition exercise, we have an addition between two halves that will give us a whole number, so:
Now we will get the exercise:
Let's note that we can simplify the mixed fraction:
Now the exercise we get is:
Note that the right addition exercise between the fractions gives a result of a whole number, so we'll start with it:
Now we get:
According to the rules of the order of operations in arithmetic, we solve the exercise from left to right.
Let's note that:
We should obtain the following exercise:
Let's solve the exercise from left to right.
We will combine the left expression in the following way:
Now we get:
\( 6\frac{2}{6}+1\frac{2}{6}= \)
\( 2\frac{1}{3}-1\frac{2}{3}= \)
\( 10\frac{1}{2}-\frac{1}{2}= \)
\( 2\frac{2}{5}+2\frac{2}{5}= \)
\( 1\frac{2}{3}-1\frac{1}{3}= \)
\( 13\frac{2}{3}-3\frac{1}{3}= \)
\( 3\frac{1}{4}+1\frac{2}{4}= \)
\( 4\frac{1}{2}-2\frac{1}{2}= \)
\( 6+5\frac{2}{3}= \)
\( 7+2\frac{1}{3}= \)