In this article, we will teach you the basics of everything you need to know about mixed numbers.

If you wish to delve deeper into a specific topic, you can access the corresponding extensive article.

Question Types:

In this article, we will teach you the basics of everything you need to know about mixed numbers.

If you wish to delve deeper into a specific topic, you can access the corresponding extensive article.

A fraction that is greater than 1 is a fraction whose numerator is larger than its denominator, this type of fractions can be converted into mixed numbers.

**It is important that we remember similar topics:**

Multiply the whole number by the denominator.

To the obtained product, add the numerator. The final result will be the new numerator.

Nothing is changed in the denominator.

The whole number is written in the numerator and the 1 in the denominator.

You can continue reading in these articles:

Question 1

\( 7\frac{5}{6}+6\frac{2}{3}+\frac{1}{3}= \)

Question 2

\( \frac{1}{2}+3\frac{1}{2}+4\frac{2}{4}= \)

Question 3

\( \frac{1}{3}+\frac{2}{3}+2\frac{3}{4}= \)

Question 4

\( \frac{6}{7}x+\frac{8}{7}x+3\frac{2}{3}x= \)

Question 5

\( 2\times\frac{5}{7}= \)

$7\frac{5}{6}+6\frac{2}{3}+\frac{1}{3}=$

Note that the right addition exercise between the fractions gives a result of a whole number, so we'll start with it:

$6\frac{2}{3}+\frac{1}{3}=7$

Now we get:

$7\frac{5}{6}+7=14\frac{5}{6}$

$14\frac{5}{6}$

$\frac{1}{2}+3\frac{1}{2}+4\frac{2}{4}=$

According to the order of operations, we will solve the exercise from left to right.

Let's note that in the first addition exercise, we have an addition between two halves that will give us a whole number, so:

$\frac{1}{2}+3\frac{1}{2}=4$

Now we will get the exercise:

$4+4\frac{2}{4}=$

Let's note that we can simplify the mixed fraction:

$\frac{2}{4}=\frac{1}{2}$

Now the exercise we get is:

$4+4\frac{1}{2}=8\frac{1}{2}$

$8\frac{1}{2}$

$\frac{1}{3}+\frac{2}{3}+2\frac{3}{4}=$

According to the order of operations rules in arithmetic, we will solve the exercise from left to right.

Let's note that:

$\frac{1}{3}+\frac{2}{3}=\frac{3}{3}=1$

Now we'll get the exercise:

$1+2\frac{3}{4}=3\frac{3}{4}$

$3\frac{3}{4}$

$\frac{6}{7}x+\frac{8}{7}x+3\frac{2}{3}x=$

Let's solve the exercise from left to right.

We will combine the left expression in the following way:

$\frac{6+8}{7}x=\frac{14}{7}x=2x$

Now we get:

$2x+3\frac{2}{3}x=5\frac{2}{3}x$

$5\frac{2}{3}x$

$2\times\frac{5}{7}=$

$1\frac{3}{7}$

Question 1

\( 1:\frac{2}{3}= \)

Question 2

\( 3\times\frac{1}{2}= \)

Question 3

\( 4\times\frac{2}{3}= \)

Question 4

\( 1:\frac{1}{4}= \)

Question 5

\( 6\times\frac{3}{4}= \)

$1:\frac{2}{3}=$

$1\frac{1}{2}$

$3\times\frac{1}{2}=$

$1\frac{1}{2}$

$4\times\frac{2}{3}=$

$2\frac{2}{3}$

$1:\frac{1}{4}=$

$4$

$6\times\frac{3}{4}=$

$4\frac{1}{2}$

Question 1

\( 3:\frac{1}{2}= \)

Question 2

\( 7\times\frac{2}{5}= \)

Question 3

\( 3\times\frac{6}{7}= \)

Question 4

Solve:

\( 7\times\frac{3}{8}= \)

Question 5

\( 1:\frac{3}{4}= \)

$3:\frac{1}{2}=$

$6$

$7\times\frac{2}{5}=$

$2\frac{4}{5}$

$3\times\frac{6}{7}=$

$2\frac{4}{7}$

Solve:

$7\times\frac{3}{8}=$

$2\frac{5}{8}$

$1:\frac{3}{4}=$

$1\frac{1}{3}$