An exponent tells us the amount of times a number is to be multiplied by itself.

Question Types:

An exponent tells us the amount of times a number is to be multiplied by itself.

A root is the inverse operation of exponentiation, which helps us discover which number multiplied by itself gives this result.

The square root is equal to the power of 0.5.

Question 1

Choose the largest value

Question 2

Find the value of n:

\( 6^n=6\cdot6\cdot6 \)?

Question 3

Sovle:

\( 3^2+3^3 \)

Question 4

\( \sqrt{441}= \)

Question 5

What is the answer to the following?

\( 3^2-3^3 \)

Choose the largest value

Let's begin by calculating the ** numerical value** of each of the roots in the given options:

$\sqrt{25}=5\\ \sqrt{16}=4\\ \sqrt{9}=3\\$We can determine that:

5>4>3>1 __Therefore, the correct answer is option A__

$\sqrt{25}$

Find the value of n:

$6^n=6\cdot6\cdot6$?

We use the formula: $a\times a=a^2$

In the formula, we see that the power shows the number of terms that are multiplied, that is, two times

Since in the exercise we multiply 6 three times, it means that we have 3 terms.

Therefore, the power, which is n in this case, will be 3.

$n=3$

Sovle:

$3^2+3^3$

Remember that according to the order of operations, exponents precede multiplication and division, which precede addition and subtraction (and parentheses always precede everything).

So **first** **calculate** the values of the terms in the power **and then** subtract between the results:

$3^2+3^3 =9+27=36$__Therefore, the correct answer is option B.__

36

$\sqrt{441}=$

The root of 441 is 21.

$21\times21=$

$21\times20+21=$

$420+21=441$

$21$

What is the answer to the following?

$3^2-3^3$

Remember that according to the order of operations, exponents come before multiplication and division, which come before addition and subtraction (and parentheses always before everything),

So **first** **calculate** the values of the terms in the power **and then** subtract between the results:

$3^2-3^3 =9-27=-18$__Therefore, the correct answer is option A.__

$-18$

Question 1

\( (\sqrt{380.25}-\frac{1}{2})^2-11= \)

Question 2

In the figure in front of you there are 3 squares

Write down the area of the shape in potential notation

Question 3

Choose the expression that is equal to the following:

\( 2^7 \)

Question 4

\( 11^2= \)

Question 5

\( 6^2= \)

$(\sqrt{380.25}-\frac{1}{2})^2-11=$

According to the order of operations, we should first solve the expression inside of the parentheses:

$(\sqrt{380.25}-\frac{1}{2})=(19.5-\frac{1}{2})=(19)$

In the next step, we will proceed to solve the exponentiation, and finally the subtraction:

$(19)^2-11=(19\times19)-11=361-11=350$

350

In the figure in front of you there are 3 squares

Write down the area of the shape in potential notation

Using the formula for the area of a square whose side is b:

$S=b^2$In the picture, we are presented with three squares whose sides from left to right have a length of 6, 3, and 4 respectively:

Therefore the areas are:

$S_1=3^2,\hspace{4pt}S_2=6^2,\hspace{4pt}S_3=4^2$square units respectively,

Consequently the total area of the shape, composed of the three squares, is as follows:

$S_{\text{total}}=S_1+S_2+S_3=3^2+6^2+4^2$square units

__To conclude, we recognise through the rules of substitution and addition that the correct answer is answer C.__

$6^2+4^2+3^2$

Choose the expression that is equal to the following:

$2^7$

$2\cdot2\cdot2\cdot2\cdot2\cdot2\cdot2$

$11^2=$

121

$6^2=$

36

Question 1

\( \sqrt{36}= \)

Question 2

\( \sqrt{49}= \)

Question 3

\( \sqrt{64}= \)

Question 4

What is the missing exponent?

\( -7^{\square}=-49 \)

Question 5

Which of the following is equivalent to the expression below?

\( \)\( 10,000^1 \)

$\sqrt{36}=$

6

$\sqrt{49}=$

7

$\sqrt{64}=$

8

What is the missing exponent?

$-7^{\square}=-49$

2

Which of the following is equivalent to the expression below?

$10,000^1$

$10,000\cdot1$