Sarah receives a school assignment.
In the first hour, she does of the work, while in the second hour she completes of the work.
How much of the assignment does Sarah do in total?
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Sarah receives a school assignment.
In the first hour, she does of the work, while in the second hour she completes of the work.
How much of the assignment does Sarah do in total?
To solve this problem, we will add the fractions of the work Sarah completed in the first and second hours:
Therefore, Sarah completed of the assignment in total.
Complete the following exercise:
\( \frac{1}{2}:\frac{3}{5}=\text{?} \)
Because fractions represent parts of a whole, and you can only add parts that are the same size! and are different-sized pieces, so you must make them the same size first.
List the multiples of each denominator and find the smallest number that appears in both lists. For 8 and 4: multiples of 8 are 8, 16, 24... and multiples of 4 are 4, 8, 12... So LCD = 8.
That's normal! For example, if adding , the LCD would be 12. You'll need to convert both fractions to have denominator 12 before adding.
Yes, always simplify! An answer like isn't in its simplest form. Divide both numerator and denominator by their greatest common divisor to get .
Absolutely! If Sarah had completed and of her work, the total would be , meaning she did more than the full assignment!
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