Area Calculation: 4×8 Rectangle with Four Semicircles

Composite Area with Semicircle Additions

Observe the rectangle in the figure below.

A semicircle has been added to each side of the rectangle.

Determine the area of the entire shape?

444888

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 What is the total area of the shape?
00:07 The area equals the rectangle area plus the areas of 4 half-circles
00:20 Each half-circle equals its opposite one, because they are on equal sides
00:28 Therefore, this is the correct formula
00:32 Our formula is half of the circle area formula
00:37 The diameter is the rectangle side which equals 8
00:43 Let's solve using the circle area formula where the radius is 4
00:50 This is the area of half-circle 1 (and also 2 since they are equal)
00:53 Now let's use the same method to calculate the area of half-circle 3
00:57 Here the circle diameter is side 4
01:01 Let's substitute the appropriate values and solve to find the area of half-circle 3
01:05 This is the area of half-circle 3 (and also 4)
01:09 Now let's calculate the rectangle area using side(4) multiplied by side(8)
01:14 Now let's sum all the areas to find the total area of the entire shape
01:23 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Observe the rectangle in the figure below.

A semicircle has been added to each side of the rectangle.

Determine the area of the entire shape?

444888

2

Step-by-step solution

The area of the entire shape equals the area of the rectangle plus the area of each of the semicircles.

Let's begin by labelling each semicircle with a number:

4448881234Therefore, we can determine that:

The area of the entire shape equals the area of the rectangle plus 2A1+2A3

Let's proceed to calculate the area of semicircle A1:

12πr2 \frac{1}{2}\pi r^2

12π42=8π \frac{1}{2}\pi4^2=8\pi

Let's now calculate the area of semicircle A3:

12πr2 \frac{1}{2}\pi r^2

12π22=2π \frac{1}{2}\pi2^2=2\pi

Therefore the area of the rectangle equals:

4×8=32 4\times8=32

Finally we can calculate the total area of the shape:

32+2×8π+2×2π=32+16π+4π=32+20π 32+2\times8\pi+2\times2\pi=32+16\pi+4\pi=32+20\pi

3

Final Answer

32+20π 32+20\pi cm².

Key Points to Remember

Essential concepts to master this topic
  • Rectangle Area: Length × width = 4 × 8 = 32 cm²
  • Semicircle Area: Use 12πr2 \frac{1}{2}\pi r^2 where radius = half the side length
  • Check: Total = 32 + 8π + 8π + 2π + 2π = 32 + 20π ✓

Common Mistakes

Avoid these frequent errors
  • Using diameter instead of radius for semicircle area
    Don't use the full side length as radius = wrong area calculation! For side length 8, radius is 4, not 8. Using 8 gives 32π instead of 8π. Always use radius = side length ÷ 2 for semicircles attached to rectangle sides.

Practice Quiz

Test your knowledge with interactive questions

Look at the rectangle ABCD below.

Side AB is 6 cm long and side BC is 4 cm long.

What is the area of the rectangle?
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FAQ

Everything you need to know about this question

Why are the semicircle radii different sizes?

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The semicircles are attached to different sides of the rectangle! The semicircles on the 8 cm sides have radius = 4 cm, while semicircles on the 4 cm sides have radius = 2 cm.

How do I find the radius of each semicircle?

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The radius of each semicircle equals half the length of the side it's attached to. So for an 8 cm side: radius = 8 ÷ 2 = 4 cm.

Do I add all four semicircle areas?

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Yes! Since there are four separate semicircles, calculate each area using 12πr2 \frac{1}{2}\pi r^2 and add them all to the rectangle area.

Why isn't the answer just the rectangle plus a full circle?

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Because we have four separate semicircles of different sizes, not one circle! Two have radius 4 cm and two have radius 2 cm, so we can't combine them into one circle.

How can I double-check my semicircle calculations?

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Use the pattern: opposite semicircles are identical. The two on 8 cm sides both give 8π, and the two on 4 cm sides both give 2π. Total semicircle area = 2(8π) + 2(2π) = 20π.

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