Calculate Angle BAD in an Isosceles Triangle with Median AD

To determine $\angle \text{BAD}$ in triangle $ABC$, follow these steps:

• The problem states that $ABC$ is an isosceles triangle where $AB = AC$.
• $AD$ is given as the median, which also acts as the angle bisector because $ABC$ is isosceles.
• Since $\angle BAC = 70^\circ$, and $AD$ bisects $\angle BAC$, $\angle BAD = \angle CAD = \frac{\angle BAC}{2}$.
• Therefore, $\angle BAD = \frac{70^\circ}{2} = 35^\circ$.

Thus, the measure of $\angle \text{BAD}$ is $\mathbf{35^\circ}$.