Calculate Angle BAD: Quadrilateral with Algebraic Expressions x+3, 2x-2, 5x-2, and 2x+11

Question

Look at the quadrilateral below.

Calculate the size of angle BAD ∢BAD .

AAABBBCCCDDDx+32x-25x-22x+11

Video Solution

Solution Steps

00:00 Determine the size of the angle BAD
00:03 The sum of angles in a quadrilateral equals 360
00:15 Substitute in the relevant values and proceed to solve for X
00:20 Group terms
00:34 Isolate X
00:43 This is the value of X
00:50 Now substitute this X value in the expression for angle BAD and proceed to solve
01:00 This is the solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Set up the equation for the sum of the angles of a quadrilateral.
  • Step 2: Solve for the variable xx.
  • Step 3: Calculate angle BAD \angle BAD using the determined value of xx.

Now, let's work through each step:

Step 1: We know that the sum of the interior angles in a quadrilateral is 360360^\circ. Therefore, we have:

(x+3)+(2x2)+(5x2)+(2x+11)=360 (x + 3) + (2x - 2) + (5x - 2) + (2x + 11) = 360

Step 2: Simplify the equation:

x+3+2x2+5x2+2x+11=360 x + 3 + 2x - 2 + 5x - 2 + 2x + 11 = 360

10x+10=360 10x + 10 = 360

Solve for xx by subtracting 10 from both sides:

10x=350 10x = 350

Divide both sides by 10:

x=35 x = 35

Step 3: Calculate BAD \angle BAD using x=35x = 35:

BAD=x+3=35+3=38 \angle BAD = x + 3 = 35 + 3 = 38^\circ

Therefore, the solution to the problem is 38\mathbf{38^\circ}.

Answer

38