Find the vertex of the parabola
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Find the vertex of the parabola
The given equation is .
First, simplify the equation:
.
This is a linear equation in the form . However, since the problem asks about a vertex, there might be a reconsideration needed if a quadratic term is missing. Since the question specifies a parabola, let's convert back:
Let's convert this into a complete square form:
Express , assuming we meant to represent:
The vertex form representation would look like:
Hence, the vertex is .
Therefore, the vertex of the parabola is .
The following function has been graphed below:
\( f(x)=x^2-6x \)
Calculate point C.
A parabola must have an term! If you only see (not ), it's a straight line, not a parabola.
There might be a typo in the problem. The most likely intended equation is , which gives vertex (7, -7).
In , the vertex is simply (h, k). For , that's (7, -7)!
Be careful with signs! In , we have h = 7 (positive) and k = -7 (negative), giving vertex (7, -7).
The vertex is the turning point - either the highest or lowest point on the parabola. Since our coefficient of is positive, (7, -7) is the minimum point.
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