Identify the Vertex in the Equation y=(x+1)²: A Quadratic Guide

Question

Find the vertex of the parabola

$y=(x+1)^2$

00:00 Find the vertex of the parabola

00:03 We'll use the formula to describe a parabolic function

00:08 The coordinates of the vertex are (P,K)

00:13 We'll use this formula and find the vertex point

00:21 We'll notice that according to the formula P is negative

00:28 We'll substitute appropriate values according to the given data

00:37 And this is the solution to the question

The equation $y = (x+1)^2$ is already in the vertex form $y = (x-h)^2 + k$ , where $(h, k)$ is the vertex of the parabola.

By comparing, we have:

The expression inside the square is $(x+1)$ , which can be rewritten as $(x - (-1))$ . Thus, $h = -1$ .
The term $k$ is not present, which means $k = 0$ .

Therefore, the vertex $(h, k)$ of the parabola is $(-1, 0)$ .

Thus, the correct answer is $(-1, 0)$ .

$(-1,0)$