Find the vertex of the parabola
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Find the vertex of the parabola
To solve the problem, we follow these steps:
By recognizing the form of the equation and substituting the values, the vertex of the parabola is .
The following function has been plotted on the graph below:
\( f(x)=x^2-8x+16 \)
Calculate point C.
The vertex form is , so you need x minus h. To get (x+7), you need x - (-7), which means h = -7.
Think of it as "opposite day" - whatever sign you see inside the parentheses, the h-coordinate has the opposite sign. Plus becomes minus, minus becomes plus!
Then h = 3 (positive 3) and k = 8, so the vertex is (3, 8). Remember: (x-3) means h = 3, while (x+3) means h = -3.
Substitute the x-coordinate back into the equation. At x = -7: . This gives the point (-7, 15)!
Yes! If there's no coefficient in front of the squared term (or it's positive), the parabola opens upward. A negative coefficient would make it open downward.
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