Find the vertex of the parabola
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Find the vertex of the parabola
To solve this problem, we need to find the vertex of the given parabola . This equation is already in the vertex form of a parabola, . In this form, the vertex is given by the point .
Let's break it down:
Therefore, the vertex of the parabola is given by the coordinates .
Substituting and into the vertex form, we have:
Vertex:
Therefore, the correct answer is choice 1: .
The following function has been graphed below:
\( f(x)=x^2-6x \)
Calculate point C.
Look at the pattern: . The h-value is what makes the parentheses equal zero. Since we have , we need x = 7 to get zero, so h = 7!
Then you'd have , so h = -7 and k = -7. The vertex would be (-7, -7). Remember: (x+7) is the same as (x-(-7)).
Vertex form has the pattern with a perfect square and a constant. Since is already squared, no further work needed!
The vertex (7, -7) is the lowest point since the coefficient of the squared term is positive (+1). This parabola opens upward with its minimum at x = 7.
Absolutely! Substitute: . So when x = 7, y = -7, confirming our vertex is (7, -7) ✓
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