Determine the Vertex for the Parabola in Equation: y = (x-7)² - 7

Vertex Form with Coordinate Identification

Find the vertex of the parabola

y=(x7)27 y=(x-7)^2-7

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find the vertex of the parabola
00:03 We'll use the formula to describe a parabolic function
00:11 The coordinates of the vertex are (P,K)
00:14 We'll use this formula to find the vertex point
00:17 We'll substitute appropriate values according to the given data
00:20 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Find the vertex of the parabola

y=(x7)27 y=(x-7)^2-7

2

Step-by-step solution

To solve this problem, we need to find the vertex of the given parabola y=(x7)27 y = (x-7)^2 - 7 . This equation is already in the vertex form of a parabola, y=a(xh)2+k y = a(x-h)^2 + k . In this form, the vertex is given by the point (h,k)(h, k).

Let's break it down:

  • The expression inside the parentheses, (x7) (x-7) , shows that h=7h = 7.
  • The constant term outside, which is 7-7, shows that k=7k = -7.

Therefore, the vertex of the parabola is given by the coordinates (h,k)(h, k).
Substituting h=7h = 7 and k=7k = -7 into the vertex form, we have:

Vertex: (7,7)(7, -7)

Therefore, the correct answer is choice 1: (7,7) (7, -7) .

3

Final Answer

(7,7) (7,-7)

Key Points to Remember

Essential concepts to master this topic
  • Vertex Form: Pattern is y = a(x-h)² + k where vertex is (h,k)
  • Identification: From y = (x-7)² - 7, h = 7 and k = -7
  • Verification: Check that x-coordinate makes expression zero: (7-7)² = 0 ✓

Common Mistakes

Avoid these frequent errors
  • Confusing signs when identifying h-coordinate
    Don't think (x-7) means h = -7! This gives wrong vertex (-7, -7) instead of (7, -7). The minus sign is already in the pattern, so h equals the number that makes the expression zero. Always identify h as the value that makes (x-h) = 0.

Practice Quiz

Test your knowledge with interactive questions

The following function has been graphed below:

\( f(x)=x^2-6x \)

Calculate point C.

CCCAAABBB

FAQ

Everything you need to know about this question

Why is the vertex (7, -7) and not (-7, -7)?

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Look at the pattern: y=a(xh)2+k y = a(x-h)^2 + k . The h-value is what makes the parentheses equal zero. Since we have (x7) (x-7) , we need x = 7 to get zero, so h = 7!

What if the equation was y = (x+7)² - 7 instead?

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Then you'd have y=(x(7))2+(7) y = (x-(-7))^2 + (-7) , so h = -7 and k = -7. The vertex would be (-7, -7). Remember: (x+7) is the same as (x-(-7)).

How do I know this is already in vertex form?

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Vertex form has the pattern y=a(xh)2+k y = a(x-h)^2 + k with a perfect square and a constant. Since (x7)2 (x-7)^2 is already squared, no further work needed!

What does the vertex tell me about the parabola?

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The vertex (7, -7) is the lowest point since the coefficient of the squared term is positive (+1). This parabola opens upward with its minimum at x = 7.

Can I double-check my vertex by plugging in x = 7?

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Absolutely! Substitute: y=(77)27=027=7 y = (7-7)^2 - 7 = 0^2 - 7 = -7 . So when x = 7, y = -7, confirming our vertex is (7, -7)

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