Locate the Vertex of the Parabola: Analyze y = x² - 6

Question

Find the vertex of the parabola

y=x26 y=x^2-6

Video Solution

Solution Steps

00:00 Find the vertex of the parabola
00:03 Use the formula to describe the parabola function
00:09 The coordinates of the vertex are (P,K)
00:12 Use this formula and find the vertex point
00:15 Write our function as a template of the formula
00:21 Substitute appropriate values according to the given data
00:28 And this is the solution to the question

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the given information.
  • Step 2: Apply the vertex formula to find h h and k k .
  • Step 3: Determine the coordinates of the vertex.

Now, let's work through each step:
Step 1: The given quadratic equation is y=x26 y = x^2 - 6 where a=1 a = 1 , b=0 b = 0 , and c=6 c = -6 .
Step 2: We use the vertex formula:

h=b2a h = -\frac{b}{2a}
Substituting the values, h=021=0 h = -\frac{0}{2 \cdot 1} = 0 .

k=cb24a k = c - \frac{b^2}{4a}
Using the given values, k=60241=6 k = -6 - \frac{0^2}{4 \cdot 1} = -6 .

Step 3: Therefore, the vertex of the parabola is at (h,k)=(0,6) (h, k) = (0, -6) .

The solution to the problem is (0,6) (0, -6) .

Answer

(0,6) (0,-6)