Find the vertex of the parabola
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Find the vertex of the parabola
To solve for the vertex of the parabola given by the equation , we will follow these steps:
Therefore, the vertex of the parabola is at the point .
This corresponds to choice 3: .
The following function has been plotted on the graph below:
\( f(x)=x^2-8x+16 \)
Calculate point C.
The vertex has x-coordinate first, then y-coordinate. Using the formula x = -b/(2a) with b = 0 gives x = 0. Then substituting: y = (0)² + 3 = 3. So the vertex is (0,3).
When b = 0, there's no x-term in the equation. This means the parabola is perfectly centered on the y-axis, so the vertex always has x-coordinate = 0.
Think of it as "negative b over 2a": . The negative sign is crucial - don't forget it!
Since a = 1 > 0, this parabola opens upward. The vertex (0,3) is the lowest point on the graph.
Remember: (x, y) means "across, then up". The first number is how far left or right, the second is how far up or down from the origin.
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