Pinpoint the Vertex of the Quadratic Function: y = x² + 3

Vertex Form with Constant Terms

Find the vertex of the parabola

y=x2+3 y=x^2+3

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find the vertex of the parabola
00:03 Use the formula to describe the parabola function
00:07 The coordinates of the vertex are (P,K)
00:13 Use this formula and find the vertex point
00:24 Substitute appropriate values according to the given data
00:27 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Find the vertex of the parabola

y=x2+3 y=x^2+3

2

Step-by-step solution

To solve for the vertex of the parabola given by the equation y=x2+3 y = x^2 + 3 , we will follow these steps:

  • Step 1: Identify the coefficients from the equation. We have a=1 a = 1 , b=0 b = 0 , and c=3 c = 3 .
  • Step 2: Calculate the x-coordinate of the vertex using the formula x=b2a x = -\frac{b}{2a} . Since b=0 b = 0 , the formula becomes x=02×1=0 x = -\frac{0}{2 \times 1} = 0 .
  • Step 3: Find the y-coordinate of the vertex by substituting x=0 x = 0 back into the equation. Calculate y=(0)2+3=3 y = (0)^2 + 3 = 3 .

Therefore, the vertex of the parabola is at the point (0,3) (0, 3) .

This corresponds to choice 3: (0,3) (0,3) .

3

Final Answer

(0,3) (0,3)

Key Points to Remember

Essential concepts to master this topic
  • Vertex Formula: Use x = -b/(2a) to find x-coordinate of vertex
  • Technique: When b = 0, vertex x-coordinate is always x = 0
  • Check: Substitute x = 0 back: y = (0)² + 3 = 3 gives (0,3) ✓

Common Mistakes

Avoid these frequent errors
  • Confusing vertex coordinates with y-intercept
    Don't think the vertex is (3,0) just because the constant is 3! This mixes up coordinates and gives the wrong point. Always use the vertex formula x = -b/(2a), then substitute to find y-coordinate.

Practice Quiz

Test your knowledge with interactive questions

The following function has been plotted on the graph below:

\( f(x)=x^2-8x+16 \)

Calculate point C.

CCC

FAQ

Everything you need to know about this question

Why is the vertex at (0,3) and not (3,0)?

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The vertex has x-coordinate first, then y-coordinate. Using the formula x = -b/(2a) with b = 0 gives x = 0. Then substituting: y = (0)² + 3 = 3. So the vertex is (0,3).

What does it mean when b = 0 in a quadratic?

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When b = 0, there's no x-term in the equation. This means the parabola is perfectly centered on the y-axis, so the vertex always has x-coordinate = 0.

How do I remember the vertex formula?

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Think of it as "negative b over 2a": x=b2a x = -\frac{b}{2a} . The negative sign is crucial - don't forget it!

Is this parabola opening up or down?

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Since a = 1 > 0, this parabola opens upward. The vertex (0,3) is the lowest point on the graph.

What if I get confused about which coordinate is which?

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Remember: (x, y) means "across, then up". The first number is how far left or right, the second is how far up or down from the origin.

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