Determine the Vertex of the Parabola: y = (x-3)² - 1

Find the vertex of the parabola

$y=(x-3)^2-1$

To solve for the vertex of the parabola given by the equation $y = (x-3)^2 - 1$, we start by comparing the equation with the standard vertex form of a quadratic function: $y = a(x-h)^2 + k$.

In the given equation, $y = (x-3)^2 - 1$, we identify:
- $h = 3$, which corresponds to the horizontal shift of the parabola.
- $k = -1$, which represents the vertical shift.

Therefore, the vertex of the parabola is at the point $(h, k)$, which is $(3, -1)$.

Thus, the vertex of the parabola is $(3, -1)$.