Locate the Vertex: Solving y = (x-7) + 5 for the Quadratic Peak

To solve the problem of finding the vertex of the parabola given by $y = (x - 7) + 5$, we must recognize how it fits into the standard vertex form.

The given equation can be seen as $y = 1(x - 7)^2 + 0$ with an additional linear term added, but primarily it’s expressed similarly into vertex form of linear shift.

We interpret this equation as there is no quadratic term transformed with $x$. Therefore, by identifying displacement only from the linear operation where $h = 7$ yielding from $(x-7)$, and additional constant $+5$, reflecting a shift vertically without quadratic transformation here, makes vertex intuitive.

The vertex of the parabola is given by the coordinates $(7, 5)$. This matches directly with typical reading of standard parabolic equation but simplified linear understanding as $y$ transposes, consistently over $x$ interval.

With the vertex coordinates determined from what we conclude has recognizable transformational standard imitation

Therefore, the solution to the problem is clearly stated as the vertex $(7, 5)$.