Domain Analysis: Find Valid Inputs for (x-3 1/11)²

Find the positive and negative domains of the function below:

y=(x3111)2 y=\left(x-3\frac{1}{11}\right)^2

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Step-by-step written solution

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1

Understand the problem

Find the positive and negative domains of the function below:

y=(x3111)2 y=\left(x-3\frac{1}{11}\right)^2

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the expression squared in the given function.
  • Step 2: Determine when the result of this squared expression is zero or greater than zero.
  • Step 3: Identify any restriction on x x that causes y y not to be positive.

Now, let's work through each step:
Step 1: We have y=(x3111)2 y = \left(x - 3\frac{1}{11}\right)^2 . The expression inside the square is zero when x=3111 x = 3\frac{1}{11} .
Step 2: Since any real number squared is non-negative, (x3111)20 \left(x - 3\frac{1}{11}\right)^2 \geq 0 .
Step 3: The value of y y is equal to zero only when x=3111 x = 3\frac{1}{11} ; for all other x x , y>0 y > 0 .

Therefore, the negative domain, where y<0 y < 0 , does not exist in this function, because y y can never be negative.
For positive domain, the function is positive for any x3111 x \neq 3\frac{1}{11} , which includes all x>0 x > 0 except for x=3111 x = 3\frac{1}{11} .

Conclusively, the positive and negative domains are:

x<0: x < 0 : none

x>0:x3111 x > 0 : x\ne3\frac{1}{11}

3

Final Answer

x<0: x < 0 : none

x>0:x313 x > 0 : x\ne3\frac{1}{3}

Practice Quiz

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The graph of the function below intersects the X-axis at points A and B.

The vertex of the parabola is marked at point C.

Find all values of \( x \) where \( f\left(x\right) > 0 \).

AAABBBCCCX

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