Find the positive and negative domains of the function below:
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Find the positive and negative domains of the function below:
To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: We have . The expression inside the square is zero when .
Step 2: Since any real number squared is non-negative, .
Step 3: The value of is equal to zero only when ; for all other , .
Therefore, the negative domain, where , does not exist in this function, because can never be negative.
For positive domain, the function is positive for any , which includes all except for .
Conclusively, the positive and negative domains are:
none
none
The graph of the function below does not intersect the \( x \)-axis.
The parabola's vertex is marked A.
Find all values of \( x \) where
\( f\left(x\right) > 0 \).
Because we're squaring the expression ! Any real number squared is always positive or zero, never negative. Think: (-5)² = 25, (0)² = 0, (7)² = 49.
The positive domain includes all x-values where y > 0. Since our function only equals zero when , the positive domain is all real numbers except that one point.
Set the squared expression equal to zero: . This happens only when , so .
This means there are no negative x-values where y < 0. The function is never negative anywhere, including when x < 0. The function is positive for all x except the one point where it equals zero.
means 3 and 1/11, while means 3 and 1/3. These are different numbers! but .
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