Domain Analysis: Find Valid Inputs for (x-3 1/11)²

Quadratic Functions with Domain Restrictions

Find the positive and negative domains of the function below:

y=(x3111)2 y=\left(x-3\frac{1}{11}\right)^2

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Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Find the positive and negative domains of the function below:

y=(x3111)2 y=\left(x-3\frac{1}{11}\right)^2

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the expression squared in the given function.
  • Step 2: Determine when the result of this squared expression is zero or greater than zero.
  • Step 3: Identify any restriction on x x that causes y y not to be positive.

Now, let's work through each step:
Step 1: We have y=(x3111)2 y = \left(x - 3\frac{1}{11}\right)^2 . The expression inside the square is zero when x=3111 x = 3\frac{1}{11} .
Step 2: Since any real number squared is non-negative, (x3111)20 \left(x - 3\frac{1}{11}\right)^2 \geq 0 .
Step 3: The value of y y is equal to zero only when x=3111 x = 3\frac{1}{11} ; for all other x x , y>0 y > 0 .

Therefore, the negative domain, where y<0 y < 0 , does not exist in this function, because y y can never be negative.
For positive domain, the function is positive for any x3111 x \neq 3\frac{1}{11} , which includes all x>0 x > 0 except for x=3111 x = 3\frac{1}{11} .

Conclusively, the positive and negative domains are:

x<0: x < 0 : none

x>0:x3111 x > 0 : x\ne3\frac{1}{11}

3

Final Answer

x<0: x < 0 : none

x>0:x313 x > 0 : x\ne3\frac{1}{3}

Key Points to Remember

Essential concepts to master this topic
  • Rule: Squared expressions are always non-negative, so y ≥ 0
  • Technique: Find where y = 0 by setting (x - 3⅟₁₁)² = 0
  • Check: Test x = 3⅟₁₁: y = 0, any other x gives y > 0 ✓

Common Mistakes

Avoid these frequent errors
  • Thinking quadratic functions can have negative outputs
    Don't assume y can be negative just because x can be negative = wrong domain analysis! Any expression squared is always ≥ 0, never negative. Always remember that (expression)² ≥ 0 for all real numbers.

Practice Quiz

Test your knowledge with interactive questions

The graph of the function below does not intersect the \( x \)-axis.

The parabola's vertex is marked A.

Find all values of \( x \) where
\( f\left(x\right) > 0 \).

AAAX

FAQ

Everything you need to know about this question

Why can't this function ever be negative?

+

Because we're squaring the expression (x3111) (x - 3\frac{1}{11}) ! Any real number squared is always positive or zero, never negative. Think: (-5)² = 25, (0)² = 0, (7)² = 49.

What does 'positive domain' mean exactly?

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The positive domain includes all x-values where y > 0. Since our function only equals zero when x=3111 x = 3\frac{1}{11} , the positive domain is all real numbers except that one point.

How do I find where the function equals zero?

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Set the squared expression equal to zero: (x3111)2=0 (x - 3\frac{1}{11})^2 = 0 . This happens only when x3111=0 x - 3\frac{1}{11} = 0 , so x=3111 x = 3\frac{1}{11} .

Why does the answer say 'x < 0: none'?

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This means there are no negative x-values where y < 0. The function is never negative anywhere, including when x < 0. The function is positive for all x except the one point where it equals zero.

What's the difference between 3⅟₁₁ and 3⅓?

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3111 3\frac{1}{11} means 3 and 1/11, while 313 3\frac{1}{3} means 3 and 1/3. These are different numbers! 31113.09 3\frac{1}{11} ≈ 3.09 but 3133.33 3\frac{1}{3} ≈ 3.33 .

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