Find the Domain of (x+15)²+6: Analyzing Valid Input Values

Quadratic Functions with Positive Range

Find the positive and negative domains of the function below:

y=(x+15)2+6 y=\left(x+15\right)^2+6

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Step-by-step written solution

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1

Understand the problem

Find the positive and negative domains of the function below:

y=(x+15)2+6 y=\left(x+15\right)^2+6

2

Step-by-step solution

To determine the positive and negative domains of the function y=(x+15)2+6 y=(x+15)^2+6 , we start by analyzing its structure.

The function is given in vertex form, y=a(xh)2+k y=a(x-h)^2+k , where a=1 a=1 , h=15 h=-15 , and k=6 k=6 . Since a=1>0 a=1 > 0 , the parabola opens upwards.

1. Vertex and Axis of Symmetry:
- Vertex: The vertex of the parabola is at (15,6)(-15, 6). This indicates the minimum point since the parabola opens upwards.

2. Range of the function:
- As (x+15)2(x+15)^2 is always zero or positive, the smallest value for y y is when (x+15)2=0(x+15)^2=0, thus y=6 y=6 . Hence, y6 y \geq 6 .

3. Analyzing the function's values:
- Since the minimum value of y y is 6 and it increases as x x moves away from -15 in either direction, the function does not achieve any negative values.

4. Conclusion:
- The function is always positive, y6 y \geq 6 .

Based on this analysis:

Negative domain: The function does not have any negative values, thus, for x<0 x < 0 , there are no values where the function is negative.

Positive domain: The entire domain is positive. Therefore, for x>0 x > 0 , the function remains positive for all x x .

Thus, the positive and negative domains are:

x<0: x < 0 : None

x>0: x > 0 : All x x

3

Final Answer

x<0: x < 0 : None

x>0: x > 0 : All x x

Key Points to Remember

Essential concepts to master this topic
  • Vertex Form: y = a(x-h)² + k shows vertex at (h,k)
  • Range Analysis: Since a = 1 > 0, minimum y-value is k = 6
  • Domain Check: Function is defined for all real x values ✓

Common Mistakes

Avoid these frequent errors
  • Confusing domain with range of function values
    Don't think domain restrictions apply when asking about positive/negative domains = missing the point entirely! This confuses where the function exists versus where it's positive/negative. Always analyze the y-values (range) to determine where the function is positive or negative.

Practice Quiz

Test your knowledge with interactive questions

The graph of the function below does not intersect the \( x \)-axis.

The parabola's vertex is marked A.

Find all values of \( x \) where
\( f\left(x\right) > 0 \).

AAAX

FAQ

Everything you need to know about this question

What's the difference between domain and positive/negative domains?

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The domain is all x-values where the function exists. The positive/negative domains ask which x-values make y positive or negative. This function exists for all real numbers but is only positive!

Why is the function never negative if it goes down to y = 6?

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Because the vertex is at (15,6)(-15, 6) and the parabola opens upward! The minimum y-value is 6, so y can never be less than 6. Since 6 > 0, the function is always positive.

How do I find where a parabola is positive or negative?

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First find the vertex and determine if it opens up or down. If it opens up and the vertex y-coordinate is positive, the whole function is positive. If negative, find where it crosses the x-axis.

What does 'None' mean for the negative domain?

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'None' means there are no x-values that make this function negative. Since y=(x+15)2+6y = (x+15)^2 + 6 is always ≥ 6, it's never negative for any x-value.

Can a quadratic function be always positive?

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Yes! When a parabola opens upward (a > 0) and its vertex is above the x-axis (k > 0), the entire function stays positive. It never touches or goes below the x-axis.

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