Find the Domain of (x+2.7)² + 0.4: Analyzing Function Inputs

Quadratic Functions with Positive Range Analysis

Find the positive and negative domains of the function below:

y=(x+2.7)2+0.4 y=\left(x+2.7\right)^2+0.4

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Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Find the positive and negative domains of the function below:

y=(x+2.7)2+0.4 y=\left(x+2.7\right)^2+0.4

2

Step-by-step solution

To solve this problem, we need to determine the domains for the given function y=(x+2.7)2+0.4 y = (x + 2.7)^2 + 0.4 where y y is positive and negative.

The function is a quadratic function in the form y=(x+h)2+k y = (x + h)^2 + k , representing a parabola opening upwards. The vertex of this parabola is at x=2.7 x = -2.7 and y=0.4 y = 0.4 , meaning this point is the minimum point of the parabola.

The y y -value of the function at its minimum is y=0.4 y = 0.4 . Because the parabola opens upwards, it implies that for all x x , y0.4 y \geq 0.4 .

Since the minimum value of y y is 0.4, the function never takes negative values; therefore, there is no negative domain.

The positive domain, x>0 x > 0 , can be interpreted as being satisfied by all x x , since no values make y y less than 0. The function's range is therefore always positive, including its minimum value.

Conclusively, the positive domain is all x x , while the function has no negative domain.

Thus, the final solution is:

x>0: x > 0 : all x x

x<0: x < 0 : none

3

Final Answer

x>0: x > 0 : all x x

x<0: x < 0 : none

Key Points to Remember

Essential concepts to master this topic
  • Vertex Form: Identify minimum value from k in y = (x+h)² + k
  • Technique: At vertex x = -2.7, minimum y = 0.4 > 0
  • Check: Since minimum is 0.4, function never reaches negative values ✓

Common Mistakes

Avoid these frequent errors
  • Confusing domain restrictions with range restrictions
    Don't think x = -2.7 creates a domain restriction = wrong exclusion! The vertex point doesn't restrict input values, it just shows the minimum output. Always remember that quadratic functions accept all real numbers as inputs.

Practice Quiz

Test your knowledge with interactive questions

The graph of the function below does not intersect the \( x \)-axis.

The parabola's vertex is marked A.

Find all values of \( x \) where
\( f\left(x\right) > 0 \).

AAAX

FAQ

Everything you need to know about this question

Why doesn't the vertex at x = -2.7 create a domain restriction?

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The vertex is just the turning point of the parabola! Unlike fractions or square roots, quadratic functions can accept any real number as input. The vertex tells us about the output range, not input restrictions.

What does 'positive domain' and 'negative domain' actually mean?

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Positive domain: all x-values where y > 0
Negative domain: all x-values where y < 0

Since our minimum y-value is 0.4, the function is always positive, so there's no negative domain!

How do I know the parabola opens upward?

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Look at the coefficient of the squared term! Since (x+2.7)2 (x+2.7)^2 has a positive coefficient of 1, the parabola opens upward, creating a minimum point at the vertex.

Could this function ever equal zero?

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No! The minimum value is y=0.4 y = 0.4 , which is above zero. Since the parabola opens upward, all other points are even higher. This function never touches the x-axis.

What if the question asked about x > 0 vs x < 0 instead?

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That would be asking about input values (domain), not output values (range)! For any quadratic function like this, both positive and negative x-values are allowed as inputs.

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