Find the Domain of y=-(x+6½)²-2¼: Complete Function Analysis

Find the positive and negative domains of the function below:

y=(x+612)2214 y=-\left(x+6\frac{1}{2}\right)^2-2\frac{1}{4}

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Step-by-step written solution

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1

Understand the problem

Find the positive and negative domains of the function below:

y=(x+612)2214 y=-\left(x+6\frac{1}{2}\right)^2-2\frac{1}{4}

2

Step-by-step solution

To solve this problem, we'll determine the domains where the function is positive or negative:

  • Given the function y=(x+612)2214 y = -\left(x + 6\frac{1}{2}\right)^2 - 2\frac{1}{4} , it's in vertex form, with a=1 a = -1 .
  • The vertex is at (x,y)=(612,214) \left(x, y\right) = \left(-6\frac{1}{2}, -2\frac{1}{4}\right) , and since a<0 a < 0 , the parabola opens downward.
  • Because the parabola opens downward and has no x-intercepts due to k<0 k < 0 , the function y=0 y = 0 is never zero nor positive.
  • This implies there are no values of x x for which y>0 y > 0 . Therefore, the positive domain is nonexistent.
  • Thus, the negative domain encompasses all x x such that y0 y \leq 0 , which is the entire set of real numbers.

Since the function's value is never positive, the correct description of positive and negative domains is as follows:
Positive domain: None
Negative domain: For all x x

Therefore, the solution is:

x<0: x < 0 : for all x x

x>0: x > 0 : none

3

Final Answer

x<0: x < 0 : for all x x

x>0: x > 0 : none

Practice Quiz

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The graph of the function below intersects the X-axis at points A and B.

The vertex of the parabola is marked at point C.

Find all values of \( x \) where \( f\left(x\right) > 0 \).

AAABBBCCCX

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