Identify the Correct Equation: Linking X and Y with Table Data

Linear Functions with Table Analysis

Which of the following equations corresponds to the function represented in the table?

XY-404812-3-2-101

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:21 Let's find the right equation for the function in this table.
00:26 First, we need to determine the slope of the graph.
00:29 We'll use a formula to calculate the graph's slope.
00:33 Let's plug in the correct values from our data to find the slope.
00:41 This is the slope of our graph.
00:48 Next, let's choose a specific point on the graph.
00:53 We'll use a linear equation here.
00:56 Now, substitute the values and solve for B, the intercept.
01:08 Here's the value of B, which is where the line hits the Y-axis.
01:13 Finally, construct the linear equation with the values we've found.
01:18 And that's how we solve this problem!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Which of the following equations corresponds to the function represented in the table?

XY-404812-3-2-101

2

Step-by-step solution

To determine the correct function, we first observe the changes in X X and their corresponding changes in Y Y . This can help us establish the slope of the function.

Let's calculate the slope m m using two points from the table. From X=4 X = -4 to X=0 X = 0 , Y Y changes from -3 to -2, resulting in a change of 1 in Y Y and 4 in X X . Hence the slope m=14 m = \frac{1}{4} .

Now, let's use the point (0,2) (0, -2) to find the y-intercept c c in the equation y=mx+c y = mx + c . Substituting m=14 m = \frac{1}{4} and point (0,2) (0, -2) in, we solve for c c :

2=14(0)+c -2 = \frac{1}{4}(0) + c
c=2 c = -2

This gives us the equation y=14x2 y = \frac{1}{4}x - 2 .

Let's verify this equation against other points in the table:

  • For X=4 X = 4 : y=14(4)2=12=1 y = \frac{1}{4}(4) - 2 = 1 - 2 = -1 . ✓
  • For X=8 X = 8 : y=14(8)2=22=0 y = \frac{1}{4}(8) - 2 = 2 - 2 = 0 . ✓
  • For X=12 X = 12 : y=14(12)2=32=1 y = \frac{1}{4}(12) - 2 = 3 - 2 = 1 . ✓

All table values satisfy the equation y=14x2 y = \frac{1}{4}x - 2 .

Therefore, the function that corresponds to the table is: y=14x2 y = \frac{1}{4}x - 2 .

3

Final Answer

y=14x2 y=\frac{1}{4}x-2

Key Points to Remember

Essential concepts to master this topic
  • Pattern Recognition: Calculate slope using any two points from table
  • Technique: Use slope formula: m = (y₂-y₁)/(x₂-x₁) = 1/4
  • Verification: Test all table points: y = ¼(12) - 2 = 1 ✓

Common Mistakes

Avoid these frequent errors
  • Using wrong points for slope calculation
    Don't pick random points or calculate slope incorrectly = wrong equation! This leads to equations that don't match the table data. Always use the slope formula carefully with correct coordinates and verify your slope with multiple point pairs.

Practice Quiz

Test your knowledge with interactive questions

Determine whether the given graph is a function?

–7–7–7–6–6–6–5–5–5–4–4–4–3–3–3–2–2–2–1–1–1111222333444555666777–4–4–4–3–3–3–2–2–2–1–1–1111222333000

FAQ

Everything you need to know about this question

How do I find the slope from a table?

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Pick any two points from the table and use the formula: m=y2y1x2x1 m = \frac{y_2 - y_1}{x_2 - x_1} . For example, using (-4, -3) and (0, -2): m=2(3)0(4)=14 m = \frac{-2 - (-3)}{0 - (-4)} = \frac{1}{4}

What's the easiest way to find the y-intercept?

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Look for the point where x = 0 in your table! That y-value is your y-intercept. In this table, when x = 0, y = -2, so the y-intercept is -2.

Why should I check all the points?

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Verification is crucial! If your equation doesn't work for all points in the table, you made an error. Always substitute each x-value and confirm you get the correct y-value.

What if I get a different slope using different points?

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If you get different slopes, double-check your arithmetic! For a linear function, the slope should be the same between any two points. Recalculate carefully using the slope formula.

Can I use the point-slope form instead?

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Absolutely! Using yy1=m(xx1) y - y_1 = m(x - x_1) with any point from the table works great. Just remember to simplify to slope-intercept form y = mx + b at the end.

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