Determine the Corresponding Equation from Tabular Function Data

Linear Equations with Tabular Data

Which of the following equations corresponds to the function represented in the table?

XY-2-1012-4-3-2-10

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find the appropriate equation for the function in the table
00:03 We want to find the slope of the graph
00:06 We'll use the formula to find the function graph slope
00:10 We'll substitute appropriate values according to the data and solve to find the slope
00:20 This is the graph's slope
00:27 Let's take a point on the graph
00:32 We'll use the linear equation
00:37 We'll substitute appropriate values and solve for B
00:46 This is the value of B (the Y-axis intercept)
00:49 We'll construct the linear equation using the values we found
00:55 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Which of the following equations corresponds to the function represented in the table?

XY-2-1012-4-3-2-10

2

Step-by-step solution

To determine the equation corresponding to the values in the table, let's analyze the relationship between X and Y:

  • Step 1: Check the change in Y with respect to X. The values show that each time X increases by 1, Y increases by 1, indicating a consistent change.
  • Step 2: Calculate the slope m m . Since the change is constant: Δy/Δx=1/1=1 \Delta y / \Delta x = 1 / 1 = 1. Thus, the slope m=1 m = 1 .
  • Step 3: Determine the y-intercept b b . When X is 0, Y is -2. Thus, b=2 b = -2 .
  • Step 4: Formulate the equation.
  • Using the slope-intercept form, y=mx+b y = mx + b , where m=1 m = 1 and b=2 b = -2 , the equation of the line is y=x2 y = x - 2 .

Verification with the table: - Substituting X=2 X = -2 yields Y=22=4 Y = -2 - 2 = -4 , which matches the table. - Similarly, substituting other values confirms consistency. Hence, this confirms our linear equation.

The corresponding equation for the function represented in the table is therefore y=x2 y = x - 2 .

3

Final Answer

y=x2 y=x-2

Key Points to Remember

Essential concepts to master this topic
  • Pattern Recognition: Look for consistent change between consecutive x and y values
  • Slope Calculation: Use m=ΔyΔx=11=1 m = \frac{\Delta y}{\Delta x} = \frac{1}{1} = 1 for this table
  • Verification: Substitute each table point into your equation: y=x2 y = x - 2

Common Mistakes

Avoid these frequent errors
  • Confusing slope direction or y-intercept sign
    Don't assume the y-intercept is positive just because you see negative y-values = wrong equation! Students often write y = x + 2 instead of y = x - 2. Always identify the y-intercept as the y-value when x = 0, which is -2 in this table.

Practice Quiz

Test your knowledge with interactive questions

Determine whether the given graph is a function?

–7–7–7–6–6–6–5–5–5–4–4–4–3–3–3–2–2–2–1–1–1111222333444555666777–4–4–4–3–3–3–2–2–2–1–1–1111222333000

FAQ

Everything you need to know about this question

How do I find the slope from a table?

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Pick any two points and use slope = rise/run. For example, from (-2, -4) to (-1, -3): slope = 3(4)1(2)=11=1 \frac{-3-(-4)}{-1-(-2)} = \frac{1}{1} = 1

What if the y-intercept isn't directly shown in the table?

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Use the point-slope form! Pick any point like (1, -1) and use y(1)=1(x1) y - (-1) = 1(x - 1) , then simplify to get y=x2 y = x - 2 .

How can I tell if the relationship is actually linear?

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Check if the change in y-values is constant for equal changes in x-values. In this table, y increases by 1 each time x increases by 1, so it's definitely linear.

Why do I need to check my answer with multiple points?

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Testing just one point might work by coincidence! Always verify with at least 2-3 points from the table to make sure your equation is correct.

What if I get confused about which variable is which?

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Remember: x is the input, y is the output. In tables, x-values are usually in the top row, y-values in the bottom row. The equation predicts y based on x.

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