Identify the Equation that Matches the Function in the Table of X and Y

Linear Equations with Table Values

Which of the following equations corresponds to the function represented in the table?

XY01234-5-3-113

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find the appropriate equation for the function in the table
00:03 We want to find the slope of the graph
00:08 We'll use the formula to find the function graph's slope
00:12 We'll substitute appropriate values according to the given data and solve to find the slope
00:19 This is the slope of the graph
00:25 Let's take a point on the graph
00:29 We'll use the linear equation
00:34 We'll substitute appropriate values and solve for B
00:45 This is the value of B (intersection point with Y-axis)
00:50 We'll construct the linear equation using the values we found
00:55 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Which of the following equations corresponds to the function represented in the table?

XY01234-5-3-113

2

Step-by-step solution

To determine the correct equation for the function represented by the table, we will follow these steps:

  • Step 1: Identify the pattern by calculating the slope m m .

  • Step 2: Determine the y-intercept c c .

  • Step 3: Select the equation that consistently matches all pairs in the table.

Step 1: Finding the slope m m
The slope m m of a linear function y=mx+c y = mx + c is given by the change in Y Y over the change in X X . Let's compute the slope between any two points from the table, say between (0,5) (0, -5) and (1,3) (1, -3) :

m=ΔYΔX=3(5)10=21=2 m = \frac{\Delta Y}{\Delta X} = \frac{-3 - (-5)}{1 - 0} = \frac{2}{1} = 2

Step 2: Determining the y-intercept c c
Using the point (0,5) (0, -5) , we can find the y-intercept directly since X=0 X = 0 :

Y=2×0+c=5 Y = 2 \times 0 + c = -5

So, c=5 c = -5 .

Step 3: Verifying Equation Match
The linear equation becomes y=2x5 y = 2x - 5 . Substitute the remaining pairs:

- For X=1 X = 1 , Y=2(1)5=25=3 Y = 2(1) - 5 = 2 - 5 = -3

- For X=2 X = 2 , Y=2(2)5=45=1 Y = 2(2) - 5 = 4 - 5 = -1

- For X=3 X = 3 , Y=2(3)5=65=1 Y = 2(3) - 5 = 6 - 5 = 1

- For X=4 X = 4 , Y=2(4)5=85=3 Y = 2(4) - 5 = 8 - 5 = 3

All pairs check out, confirming y=2x5 y = 2x - 5 aligns perfectly.

Therefore, the solution to the problem is y=2x5 y = 2x - 5 .

3

Final Answer

y=2x5 y=2x-5

Key Points to Remember

Essential concepts to master this topic
  • Slope Formula: Use any two points to find m = (y₂-y₁)/(x₂-x₁)
  • Y-Intercept: When x = 0, y = -5, so c = -5
  • Verification: Test all points: (1,-3), (2,-1), (3,1), (4,3) in y = 2x - 5 ✓

Common Mistakes

Avoid these frequent errors
  • Using wrong slope calculation
    Don't calculate slope as (x₂-x₁)/(y₂-y₁) = wrong fraction! This reverses rise over run and gives completely wrong equations. Always use slope = (y₂-y₁)/(x₂-x₁) = rise over run.

Practice Quiz

Test your knowledge with interactive questions

Determine whether the following table represents a constant function:

XY02468-3-3-3-3-3

FAQ

Everything you need to know about this question

How do I find the slope from a table of values?

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Pick any two points from the table and use the slope formula: m=y2y1x2x1 m = \frac{y_2 - y_1}{x_2 - x_1} . For example, using (0,-5) and (1,-3): m=3(5)10=21=2 m = \frac{-3-(-5)}{1-0} = \frac{2}{1} = 2 .

What if I get different slopes using different points?

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If you get different slopes, the relationship isn't linear! For a linear function, the slope should be the same between any two points. Double-check your calculations.

How do I find the y-intercept from the table?

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Look for the point where x = 0. The y-value at that point is your y-intercept. In this table, when x = 0, y = -5, so the y-intercept is -5.

What if x = 0 isn't in my table?

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Use the equation y=mx+c y = mx + c with any point from the table. Substitute the x and y values plus your slope to solve for c. For example: 3=2(1)+c -3 = 2(1) + c , so c=5 c = -5 .

Why should I check all the points?

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Testing all points ensures your equation is completely correct. Even if one point works, others might not if you made an error. A correct linear equation will satisfy every single point in the table.

Can I use any two points to find the slope?

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Yes! For a linear function, any two points will give you the same slope. It's often easiest to use consecutive points or points with simple coordinates to minimize calculation errors.

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