Simplify the Expression: (log₄5 + log₄2)/(3log₄2)

log45+log423log42= \frac{\log_45+\log_42}{3\log_42}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve
00:03 We'll use the formula for logical addition, we'll get the log of their product
00:15 We'll use the formula for the log of a power, we'll move the 3 inside the log
00:25 We'll calculate the power
00:29 We'll use the formula for logical division
00:32 We'll get the log of the numerator with base of the denominator
00:37 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

log45+log423log42= \frac{\log_45+\log_42}{3\log_42}=

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Combine the logarithms in the numerator.
  • Step 2: Simplify the expression using logarithmic properties.

Now, let's work through each step:

Step 1: Combine the logarithms in the numerator using the sum of logarithms property:

log45+log42=log4(5×2)=log410.\log_45 + \log_42 = \log_4(5 \times 2) = \log_4 10.

Step 2: Simplify the entire expression log4103log42\frac{\log_4 10}{3\log_4 2}:

log4103log42=log410log423=log410log48=log810.\frac{\log_4 10}{3 \log_4 2} = \frac{\log_4 10}{\log_4 2^3} = \frac{\log_4 10}{\log_4 8} = \log_8 10.

This follows from the property that logbxlogby=logyx\frac{\log_b x}{\log_b y} = \log_y x.

Therefore, the solution to the problem is log810\log_8 10.

3

Final Answer

log810 \log_810

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\( \frac{1}{\log_49}= \)

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