Solve the Inverse Logarithm: Finding (log₇x)⁻¹

Question

(log7x)1= (\log_7x)^{-1}=

Video Solution

Solution Steps

00:05 Let's solve a math problem together!
00:09 We'll use a formula to change a negative power into a fraction.
00:14 Now, let's apply this formula in our exercise.
00:21 Next, we'll divide 1 by the logarithm. Let's follow the formula.
00:26 Remember to switch the number and base for the logarithm.
00:31 We'll use this rule in our practice problem.
00:35 And that's how we find the solution to this question!

Step-by-Step Solution

To solve this problem, we must determine the reciprocal of the logarithm expression log7x \log_7 x . This involves finding the inverse using the properties of logarithms.

  • Step 1: Recognize that the expression (log7x)1 (\log_7 x)^{-1} is asking for the reciprocal of the logarithm.
  • Step 2: Apply the inverse property of logarithms: (logba)1=logab(\log_b a)^{-1} = \log_a b.

Applying this property to our problem, we set b=7b = 7 and a=xa = x. Therefore, (log7x)1(\log_7 x)^{-1} transforms to:

logx7 \log_x 7

Thus, the value of the expression (log7x)1 (\log_7 x)^{-1} is logx7 \log_x 7 .

Therefore, the solution to the problem is logx7 \log_x 7 .

Answer

logx7 \log_x7