Solve the Inverse Logarithm: Finding (log₇x)⁻¹

Question

(log7x)1= (\log_7x)^{-1}=

Video Solution

Solution Steps

00:00 Solve
00:04 We'll use the formula to convert from negative power to fraction
00:09 We'll use this formula in our exercise
00:16 We'll use the formula of dividing 1 by log
00:21 We'll get the log of the number and base reversed
00:26 We'll use this formula in our exercise
00:30 And this is the solution to the question

Step-by-Step Solution

To solve this problem, we must determine the reciprocal of the logarithm expression log7x \log_7 x . This involves finding the inverse using the properties of logarithms.

  • Step 1: Recognize that the expression (log7x)1 (\log_7 x)^{-1} is asking for the reciprocal of the logarithm.
  • Step 2: Apply the inverse property of logarithms: (logba)1=logab(\log_b a)^{-1} = \log_a b.

Applying this property to our problem, we set b=7b = 7 and a=xa = x. Therefore, (log7x)1(\log_7 x)^{-1} transforms to:

logx7 \log_x 7

Thus, the value of the expression (log7x)1 (\log_7 x)^{-1} is logx7 \log_x 7 .

Therefore, the solution to the problem is logx7 \log_x 7 .

Answer

logx7 \log_x7