Look at the function below:
Then determine for which values of the following is true:
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Look at the function below:
Then determine for which values of the following is true:
To solve this problem, we analyze the function .
Notice that this function involves a squared term, , which is squared to yield the expression . A crucial property of squares is that the square of any real number is never negative. Thus, for any real number , .
Since is the square of a real expression, it implies that this expression is always greater than or equal to zero. Therefore, it is impossible for to be less than zero. There are no real values of that would satisfy the inequality .
Consequently, the correct interpretation is that the inequality holds true for no values of .
Therefore, the solution to the problem is:
True for no values of
True for no values of
The graph of the function below does not intersect the \( x \)-axis.
The parabola's vertex is marked A.
Find all values of \( x \) where
\( f\left(x\right) > 0 \).
When you multiply any real number by itself, the result is always positive or zero. For example: , , and . This is a fundamental property of real numbers!
It means the inequality has no solution. No matter what real number you substitute for x, the expression will never be less than zero. The solution set is empty.
Then you'd solve ! This gives , so . But our question asks for when it's less than zero, which never happens.
The graph of is a parabola opening upward with vertex at (-15, 0). Since it never goes below the x-axis, there are no points where y < 0.
No exceptions with real numbers! However, in advanced mathematics with complex numbers, squares can be negative. But for this problem, we're working with real numbers only.
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