Solve for a: Division of Logarithms with Base 7 and 9 Equation

Logarithmic Properties with Change of Base

4a2log79 ⁣:log97=16 \frac{4a^2}{\log_79}\colon\log_97=16

Calculate a.

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find A
00:04 Let's break down the multiplication from the fraction
00:19 We'll use the formula of dividing 1 by log
00:24 We'll get the log of the number and base reversed
00:29 We'll use this formula in our exercise
00:49 Isolate A
00:54 When extracting a root there are always 2 solutions, positive and negative
01:04 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

4a2log79 ⁣:log97=16 \frac{4a^2}{\log_79}\colon\log_97=16

Calculate a.

2

Step-by-step solution

The given problem requires us to solve for a a from the equation:

4a2log79:log97=16\frac{4a^2}{\log_7 9} : \log_9 7 = 16.

First, recognize that the expression  ⁣:\colon represents division, thus:

4a2log79=log97×16.\frac{4a^2}{\log_7 9} = \log_9 7 \times 16.

From the property of logarithms, we know log97=1log79\log_9 7 = \frac{1}{\log_7 9}. Hence, we can express the equation as:

4a2log79=16log79.\frac{4a^2}{\log_7 9} = \frac{16}{\log_7 9}.

By equating both sides and simplifying, we get:

4a2=16.4a^2 = 16.

Solving for a2 a^2 gives:

a2=4.a^2 = 4.

Taking the square root of both sides, we find:

a=±2.a = \pm2.

Therefore, the value of a a is ±2 \pm 2 .

3

Final Answer

±2 \pm2

Key Points to Remember

Essential concepts to master this topic
  • Property: log97=1log79 \log_9 7 = \frac{1}{\log_7 9} by change of base rule
  • Technique: Recognize division symbol (:) means 4a2log79÷log97=16 \frac{4a^2}{\log_7 9} ÷ \log_9 7 = 16
  • Check: Substitute a=±2 a = ±2 : 4(±2)2=16 4(±2)^2 = 16

Common Mistakes

Avoid these frequent errors
  • Misinterpreting the colon symbol as multiplication
    Don't treat : as multiplication = wrong setup entirely! The colon (:) means division, not multiplication, so 4a2log79:log97 \frac{4a^2}{\log_7 9} : \log_9 7 becomes 4a2log79÷log97 \frac{4a^2}{\log_7 9} ÷ \log_9 7 . Always recognize that division by a fraction equals multiplication by its reciprocal.

Practice Quiz

Test your knowledge with interactive questions

\( \log_{10}3+\log_{10}4= \)

FAQ

Everything you need to know about this question

What does the colon symbol (:) mean in this equation?

+

The colon (:) represents division! So A:B A : B means A÷B A ÷ B . This notation is common in some countries but might look unfamiliar.

How do I use the property log97=1log79 \log_9 7 = \frac{1}{\log_7 9} ?

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This comes from the change of base formula! When you have logab \log_a b and logba \log_b a , they are reciprocals of each other. So log97×log79=1 \log_9 7 \times \log_7 9 = 1 .

Why do I get both positive and negative answers?

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Because we're solving a2=4 a^2 = 4 ! When you take the square root of both sides, you get two solutions: a=+2 a = +2 and a=2 a = -2 . Both work because (+2)2=(2)2=4 (+2)^2 = (-2)^2 = 4 .

How can I verify my answer is correct?

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Substitute back into the simplified equation! We found 4a2=16 4a^2 = 16 , so check: 4(±2)2=4(4)=16 4(±2)^2 = 4(4) = 16 ✓. Both values work!

What if I don't remember the logarithm property?

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You can use the change of base formula: logab=logbloga \log_a b = \frac{\log b}{\log a} . So log97=log7log9 \log_9 7 = \frac{\log 7}{\log 9} and log79=log9log7 \log_7 9 = \frac{\log 9}{\log 7} - notice they're reciprocals!

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