Solve the Equation: 1/x + x² = 9/x in Rational Form

Cubic Equations with Fractional Terms

1x+x2=9x \frac{1}{x}+x^2=\frac{9}{x}

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find X
00:03 Multiply by denominators to eliminate fractions
00:10 Simplify what's possible
00:17 Isolate X
00:26 Extract cube root
00:33 Break down 8 into 2 to the power of 3
00:38 Cube root cancels out power of 3
00:41 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

1x+x2=9x \frac{1}{x}+x^2=\frac{9}{x}

2

Step-by-step solution

To solve the equation 1x+x2=9x \frac{1}{x} + x^2 = \frac{9}{x} , we follow these steps:

  • Step 1: Eliminate the fractions by multiplying both sides of the equation by x x , yielding 1+x3=9 1 + x^3 = 9 .
  • Step 2: Rearrange the equation to standard form: x3+1=9 x^3 + 1 = 9 . Simplify this to x3=8 x^3 = 8 .
  • Step 3: Solve for x x by taking the cube root of both sides: x=83 x = \sqrt[3]{8} or simply x=2 x = 2 .

Thus, the solution to the equation 1x+x2=9x \frac{1}{x} + x^2 = \frac{9}{x} is x=2 x = 2 .

3

Final Answer

x=2 x=2

Key Points to Remember

Essential concepts to master this topic
  • Elimination: Multiply both sides by x to clear all fractions
  • Technique: Rearrange 1+x3=9 1 + x^3 = 9 to get x3=8 x^3 = 8
  • Check: Substitute x = 2: 12+4=92 \frac{1}{2} + 4 = \frac{9}{2} gives 92=92 \frac{9}{2} = \frac{9}{2}

Common Mistakes

Avoid these frequent errors
  • Forgetting to multiply all terms by x
    Don't multiply only the fractions by x and leave x² unchanged = wrong equation! This creates 1+x2x=9 1 + x^2 \cdot x = 9 instead of the correct 1+x3=9 1 + x^3 = 9 . Always multiply every single term on both sides by x.

Practice Quiz

Test your knowledge with interactive questions

Determine if the simplification shown below is correct:

\( \frac{7}{7\cdot8}=8 \)

FAQ

Everything you need to know about this question

Why can I multiply both sides by x when x could be zero?

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Great observation! We can multiply by x because we're looking for solutions where x ≠ 0. Since the original equation has fractions with x in the denominator, x = 0 would make the equation undefined anyway.

How do I know when to take a cube root?

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When you have x3=8 x^3 = 8 , you need to find what number cubed equals 8. Since 2 × 2 × 2 = 8, we know x=83=2 x = \sqrt[3]{8} = 2 .

Could there be other solutions besides x = 2?

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For real numbers, x = 2 is the only solution. Cubic equations can have up to 3 solutions, but in this case, the other two solutions involve complex numbers, which are beyond basic algebra.

What if I subtract 1/x from both sides instead?

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That would give you x2=8x x^2 = \frac{8}{x} , which is harder to solve! Multiplying by x first eliminates all fractions at once, making the problem much simpler.

How can I check my answer without a calculator?

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Substitute x = 2: 12+22=12+4=92 \frac{1}{2} + 2^2 = \frac{1}{2} + 4 = \frac{9}{2} and 92=92 \frac{9}{2} = \frac{9}{2} . The equation balances perfectly!

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