In front of you the next triangle:
Since AD is the median
Since the area of the triangle ADB is equal to 15.
Find the area of the triangle ABC.
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In front of you the next triangle:
Since AD is the median
Since the area of the triangle ADB is equal to 15.
Find the area of the triangle ABC.
To solve this problem, we'll employ the theorem which states that the median of a triangle divides it into two triangles of equal area. Given that is a median of , it divides into and .
Step 1: Recognize the properties of a median. The median implies:
- Area of Area of .
- Given Area of , hence Area of .
Step 2: Compute the total area of :
- Total Area of Area of Area of
Thus, the area of triangle is .
30
Is DE side in one of the triangles?
A median is a line segment from any vertex to the midpoint of the opposite side. In this case, AD goes from vertex A to point D, which is the midpoint of side BC.
Because the median splits the base in half! Both triangles ADB and ADC share the same height from A, but each has half the base (BD = DC), so their areas must be equal.
Yes! Whether the triangle is acute, obtuse, or right-angled, any median will always divide it into two triangles of equal area. This is a fundamental property.
The process is identical! If triangle ADC has area 15, then triangle ADB also has area 15, making the total area of triangle ABC equal to 30.
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